Variable coming back undefined Javascript

Question

My return variable keeps coming back undefined. Can someone please explain why? as far as I can tell it should be in scope.

var countBs = function(word) {
 var count = 0;
 for (var i = 0; i < word.length; i++){
 if (word.charAt[i] == 'B'){
 count += 1;
 return count;
 };
 };
};
console.log(countBs('BBABBAB'))

• zerkms: word.charAt is a function. When you develop - ensure you understand every expression in your code and that you have checked that every expression returns exactly what you expect - using a debugger or at least a console.log
• Adrian: @Luca Explain why? Maybe he doesn't want to iterate if a value is found?
• Stefano Tartaglia: Thank you! I just figure it out. Man what a Duh moment.
• Dennis Vash: word.charAt(i)

Answer 1

You need to return count at the end of the function, and use .charAt(i):

var countBs = function (word) {
 var count = 0;
 for (var i = 0; i < word.length; i++){
 if (word.charAt(i) == 'B'){
 count += 1;
 };
 }
 return count;
}

• Chinonso Chukwuogor: This solves the problem. but i'm still curious to know why the original code snippet returns undefined. I would expect it to return 1
• jh314: word.charAt[i] is always undefined, so the if is never true.
• Chinonso Chukwuogor: Oh. I didn't notice charAt was being used as an array. my bad