Passing value from PHP script to Python script

Question

I looked at the other questions similar to this one, but can't figure this out still.

I have a basic php file that does this:

?php
$item='example';
$tmp = exec("python testscriptphp.py .$item");
echo $tmp;
?

While succesfully calls python that I have running on my webhostserver. Now in my python script i want something like this:

item=$item
print item

Basically I'm asking how to pass variables from PHP to a python script and then back to php if necessary.

Thanks!

• netcoder: Have you heard of sys.argv (Python) and $argv (PHP) ? :)

Answer 1

Although netcoder pretty much gave you the answer in his comment, here's an example:

Python->PHP

example.py

import os
os.system("/usr/bin/php example2.php whatastorymark")

example2.php

<?php
 echo $argv[1];
?>

PHP->Python

<?php
 $item='example';
 $tmp = exec("python testscriptphp.py .$item");
 echo $tmp;
?>

testscriptphp.py

import sys
print sys.argv[1]

Here's how PHP's command line argument passing works: http://php.net/manual/en/reserved.variables.argv.php The same for Python: http://docs.python.org/library/sys.html#sys.argv

• РАВИ: is it possible to update the variable rather than echo? from python to php?
• Reigel Gallarde: @ravi I think, $argv[1] = 1234;

Answer 2

write a php file example index.php:

<?PHP
$sym = $_POST['symbols'];
echo shell_exec("python test.py .$sym");
?>

$sym is a parameter we passining to test.py python file. then create a python example test.py:

import sys
print(sys.argv[1])

I hope it help you.

Answer 3

In php file

 $a = "..\Python\Python39\python.exe ../frontend/upload/main.py '$param1''$param2'";
 $output = shell_exec($a);
 echo $output;
 ..\Python\Python39\python.exe 

python path in my system, you can change with your path

 ../frontend/upload/main.py 

it's my python script path

In python file

import sys
param_1_ = sys.argv[1]
param_2= sys.argv[2]