How to return new array from looping array indexes i and j

Question

Given an array of integers and I want to return indices of the two numbers such that they add up to a specific target. Assuming that each input would have exactly one solution, and I haven't used the same element twice.

I am using the brute force approach to Loop through each element x and find if there is another value that equals to target−x

code snippet:

var twoSum = function(nums, target) {
 for(var i ; i<nums.length ; i++){
 for(var j = i + 1; j<nums.length ; j++){
 if (nums[j]==target-nums[i]){
 // This is where I want to return new array 
 return 
 
 }
 
 }
 }
 
 };

• RobG: for(var i ; isn't going to work, you need to initialise i with a number value: for(var i=0;, otherwise you're trying to do ++undefined. You haven't actually said what the problem is or any errors you get.++undefined produces NaN, then ++NaN continues to produce NaN so i<nums.length is always false (since NaN < anything is always false.

Answer 1

You just want to return the two indices?

return [i, j];

• Rajesh Dixit: May be its an opinionated comment, but I guess this could have been a comment
• Philip Mutua: is it appropriate if I use new Array(i,j);
• Charlie Martin: Always prefer array literals [] to using the constructor in javascript. Same goes with objects. Use {} instead of new Object()