3

I have an array that I need to remove spaces from, for example it returns like

[book, row boat,rain coat]

However, I would like to remove all the white spaces.

All the guides I saw online said to use .replace, but it seems like that only works for strings. Here is my code so far.

function trimArray(wordlist)
{
 for(var i=0;i<wordlist.length;i++)
 {
 wordlist[i] = wordlist.replace(/\s+/, "");
 }
}

I have also tired replace(/\s/g, '');

Any help is greatly appreciated!

asked Dec 10, 2017 at 3:44
3
  • 1
    You need to replace individual element: wordlist[i] = wordlist[i].replace(/\s+/, "");. Try using something like map, it's a much cleaner approach. Note that your replacement function will replace any whitespace. If you want to just trim, use the trim function: wordlist[i] = wordlist[i].trim() Commented Dec 10, 2017 at 3:46
  • [book, row boat,rain coat] - Doesn't look like a string array. Is this one string or are you getting back [" book", " row", " boat", " coat"] Commented Dec 10, 2017 at 3:47
  • Do you want ALL whitespace or just the preceding and trailing whitespace? So if your array is something like this: ["cat food","dogs ","fish tank"] do you want the spaces within cat food and fish tank gone too? Or will there never be any spaces within the strings? Commented Dec 10, 2017 at 3:55

2 Answers 2

5

First and foremost you need to enclose the words in your array quotes, which will make them into strings. Otherwise in your loop you'll get the error that they're undefined variables. Alternatively this could be achieved in a more terse manner using map() as seen below:

const arr = ['book', 'row boat', 'rain coat'].map(str => str.replace(/\s/g, ''));
console.log(arr);

answered Dec 10, 2017 at 3:46
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1

This will remove all of the spaces, even those within the text:

 const result = [' book',' row boat ','rain coat '].map(str => str.replace(/\s/g, ''));
 console.log(result);

and this will only remove preceding and trailing spaces:

 const result = [' book',' row boat ','rain coat '].map(str => str.trim());
 console.log(result);

answered Dec 10, 2017 at 3:58

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