Editing hex value at a particular position in disk image file using python

Question

How do I edit hex value at a particular Sector of Disk image file (60GB) using Python?

Example:
Given 512,
File name: RAID.img
Typical File size: 60gb+
Sector: 3
Address Offset: 0000060A - 0000060F
Value: 0f, 0a , ab, cf, fe, fe

---

The code that I can think of:

fname = 'RAID.img'
with open(fname, 'r+b') as f:
 newdata = ('\x0f\x0a\xab\xcf\xfe\xfe')
 print newdata.encode('hex')

How do I modify data in Sector = 3, address is from 0000060A - 0000060F? Is there some library could use?

Answer 1

If you know the exact offset (byte position) of the data you want to update, you can use file.seek, followed by file.write:

#!/usr/bin/env python
offset = 0x60a
update = b'\x0f\x0a\xab\xcf\xfe\xfe'
with open('raid.img', 'r+b') as f:
 f.seek(offset)
 f.write(update)

---

If your data file is small (up to 1MB perhaps), you can read the complete binary file into a bytearray, play with (modify) the data in memory, then write it back to file:

#!/usr/bin/env python
offset = 0x60a
update = b'\x0f\x0a\xab\xcf\xfe\xfe'
with open('raid.img', 'r+b') as f:
 data = bytearray(f.read())
 data[offset:offset+len(update)] = update
 f.seek(0)
 f.write(data)

• Joal: Forgot to mention, my disk image is 60+gb in size
• Joal: How to i loop the first hex value (Currently 0xf) from x01 to xof ? >>> update = b'\x0f\x0a\xab\xcf\xfe\xfe'
• randomir: Sorry, I don't understand your follow-up question.
• Joal: i want to loop hex value x01 to x0f for only the first hex value AT variable " update = b'\x0f <<< this the first one ...................'"
• randomir: I'm not sure I understand that. You want to insert 15 bytes \x01...\x0f in a certain position in file?