Swift 3: Sort Ordered List of Objects by Property

Question

In Swift 3 I define my array as:

var filteredObjects = [Int: CustomObject]()

then I populate array with data:

filteredObjects[filteredObjects.count] = CustomObject

Now I want to sort array by (1) property "title" of CustomObject which is a String and (2) a float property "distance" of CustomObject.

When I try:

filteredObjects.sort({ 0ドル.distance < 1ドル.distance })

it produces error Value of tuple type (key:Int, value:CustomObject) has no member distance

I suspect I cannot use sort method like this but I cannot find the solution.

• vadian: Your array is actually a dictionary. A dictionary is unordered by definition.
• Amit: Check this : stackoverflow.com/questions/35431754/… . if it helps in your scenario.
• Leo Dabus: let sortedTuples = filteredObjects.sorted{ 0ドル.value.distance < 1ドル.value.distance }

Answer 1

In swift 3: While using sort in filteredObjects i.e dictionary 0ドル will give you a single object from filteredObjects which will be of tuple type "((key: Int, value: CustomObject), (key: Int, value: CustomObject))". 0ドル.distance will actually try to find distance property in the tuple which isn't available in the result tuple, so you are getting error Value of tuple type (key:Int, value:CustomObject) has no member distance

What you can do is

let resultDictionary = filteredObjects.sorted() { 
 0ドル.0.value.distance < 0ドル.1.value.distance 
}

0ドル.0.value is of type CustomObject which have property distance according to which you want to sort the result.

Special thanks to @Leo Dabus.

• Leo Dabus: Btw by using the parentheses you need to add the by: keyword
• Leo Dabus: And you can’t use sort. Dictionary is an unordered collection
• laxman khanal: I have already up voted your comment. I tried to explain why @Vad is getting that error.
• Leo Dabus: again by using the parentheses you need to add the by: keyword .sorted(by: { ... }) or remove the parentheses .sorted { ... }