php parsing json data

Question

Never had to do this one and getting confused about the format and how to access specific variables out of it.

The result of :

$result = json_decode($result);
print_r($result);

is :

stdClass Object
(
 [input] => stdClass Object
 (
 [address_components] => stdClass Object
 (
 [number] => 1109
 [predirectional] => N
 [street] => Highland
 [suffix] => St
 [formatted_street] => N Highland St
 [city] => Arlington
 [state] => VA
 [zip] => 22201
 [country] => US
 )
 [formatted_address] => 1109 N Highland St, Arlington, VA 22201
 )
 [results] => Array
 (
 [0] => stdClass Object
 (
 [address_components] => stdClass Object
 (
 [number] => 1109
 [predirectional] => N
 [street] => Highland
 [suffix] => St
 [formatted_street] => N Highland St
 [city] => Arlington
 [county] => Arlington County
 [state] => VA
 [zip] => 22201
 [country] => US
 )
 [formatted_address] => 1109 N Highland St, Arlington, VA 22201
 [location] => stdClass Object
 (
 [lat] => 38.886672
 [lng] => -77.094735
 )
 [accuracy] => 1
 [accuracy_type] => rooftop
 [source] => Arlington
 )
 [1] => stdClass Object
 (
 [address_components] => stdClass Object
 (
 [number] => 1109
 [predirectional] => N
 [street] => Highland
 [suffix] => St
 [formatted_street] => N Highland St
 [city] => Arlington
 [county] => Arlington County
 [state] => VA
 [zip] => 22201
 [country] => US
 )
 [formatted_address] => 1109 N Highland St, Arlington, VA 22201
 [location] => stdClass Object
 (
 [lat] => 38.886665
 [lng] => -77.094733
 )
 [accuracy] => 1
 [accuracy_type] => rooftop
 [source] => Virginia Geographic Information Network (VGIN)
 )
 )
)

How can I access the lat and lng values? I am getting confused since there are objects and arrays mixed within. I've never worked with json in this manner with php... it is a geocoding api that returns in json format.

I basically want to do something like $lat = $result['results'][0]['location']['lat']; and so on.

• Shivam Pandya: Use type casting, convert it into object

Answer 1

You have to use true as second parameter in json_decode so that output will be normal php array not stdclass array(so that you can use your approach what you are trying)

So do like below:-

$result = json_decode($result,true);
echo $lat = $result['results'][0]['location']['lat'];
echo $lng = $result['results'][0]['location']['lng'];

Note:-

1. With your current format also you can get data like below:-

echo $lat = $result->results[0]->location->lat; //using object approach 
echo $lng = $result->results[0]->location->lng; //using object approach 

2. Use foreach() to get all lat-lng records.

foreach($result->results as $val) { //if using stdclass array
 echo "Latitude = ".$val->location->lat;
 echo "Longitude = ".$val->location->lng;
}

Or:-

foreach($result['results'] as $val) {//if using normal array
 echo "Latitude = ".$val['location']['lat'];
 echo "Longitude = ".$val['location']['lng'];
}

• user756659: Knew it had to be something simple I was missing... that is what I was looking for... thanks!
• Death-is-the-real-truth: @user756659 glad to help you :):)

Answer 2

You can access lat lng from result as below

$result = json_decode($result);
echo $result->results[0]->location->lat;
echo $result->results[0]->location->lng;

Answer 3

I can see that from your example you have multiple records to fetch. Use a foreach() to print the details

$result = json_decode($result);
foreach($result->results as $value) {
 echo "Lat--",$value->location->lat; //using object
 echo "Long--",$value->location->lng;
}

Answer 4

Use second parameter as true for convert all object to array. Otherwise you can get values like this.

$result->results[0]->location->lat;
$result->results[0]->location->lng;

• Death-is-the-real-truth: it's lng not long. Now +1 because you are correct too.