0

I know that you can use ${} inside a string to put a var but here it seems it doesn't want to recognise the var and it is not in the brackets

var str = s.toLowerCase();
 var counts = {};
 var ch, index, len, count;
 for (index = 0, len = str.length; index < len; ++index) {
 ch = str.charAt(index);
 count = counts[ch];
 counts[ch] = count ? count + 1 : 1;
 }
 for (ch in counts) {
 console.log('${ch}(${counts[ch]})');
 } 
2
  • Are you sure something like this exists without defining an extra function to handle this? Commented Jul 29, 2017 at 17:55
  • 1
    It's typo , replace ' with ` Commented Jul 29, 2017 at 17:58

3 Answers 3

2

ES2015 template literals require a back tick:

console.log(`${ch}(${counts[ch]})`);

Working example:

const s = 'An example string with some duplicate characters.';
var str = s.toLowerCase();
var counts = {};
var ch, index, len, count;
for (index = 0, len = str.length; index < len; ++index) {
 ch = str.charAt(index);
 count = counts[ch];
 counts[ch] = count ? count + 1 : 1;
}
for (ch in counts) {
 console.log(`${ch}(${counts[ch]})`);
} 

answered Jul 29, 2017 at 17:57
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4 Comments

the problem is not in the brackets
What do you mean? Where is it, then?
i want to be inside 1 string
There's only one string literal. Could you please clarify what the result should look like?
1

You need to use the back tick. Use ` instead of '.

answered Jul 29, 2017 at 17:56

Comments

1

You need to put your string inside ``, not ''.

var myVar = 'hello world!';
console.log(`${myVar}`);
answered Jul 29, 2017 at 17:56

Comments

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