Executing a shell script with arguments from a python script

Question

My Shell script is executed like this from the command line

./pro.sh "Argument1"

I am calling it from my python script currently like this

subprocess.call(shlex.split('bash pro.sh "Argument1"'))

How do I pass the value of Argument1 as a variable. My argument to the script can be any string. How do I achieve this?

Answer 1

use subprocess to call your shell script

subprocess.Popen(['run.sh %s %s' % (var1, var2)], shell = True)

• RJP: My argument is a string of multiple words. When I use this, only the first word of the string is being used.
• bigbounty: U have to store the string in variable var1,var2 and then execute the script
• RJP: I have already done that. It reads only the first word of var1. var 1 contains multiple words
• bigbounty: Ohk,then it that case use subprocess.Popen(["bash", ".sh file", "Multiple Arguments"])

Answer 2

You can use

subprocess.Popen(["bash", "pro.sh", "Argument1"])

If your string argument is multiple words, it should work fine.

subprocess.Popen(["bash", "pro.sh", "Argument with multiple words"])

As long as the multiple words are in one string in the list passed to subprocess.Popen(), it is considered one argument in the argument list for the command.

You should not use shell=True unless you have a good reason. It can be a security problem if you aren't very careful how it is used.