parsing string in javascript

Question

I have string MetadataCompanyTotal which is Camel Case. I need to insert space between string.

Input is

var str="MetadataCompanyTotal";

output should be

"Metadata Company Total".

I have tried the following approach but needed a faster way with less number of lines as there is lines constraint.

My approach :

var i, 
 str="MetadataCompanyTotal",
 temp_str="",
 final_space_inserted_str="";
for(i=0; i < str.length ; i++){
 if ( str.charAt(i) === str.charAt(i).toUpperCase()){
 final_space_inserted_str += temp_str + " ";//inserting space.
 temp_str = str.charAt(i);
 }
 else{
 temp_str += str.charAt(i);
 }
}
final_space_inserted_str+=temp_str.// last word.

Is there any efficient approach in javascript?

• Thomas: str.replace(/\B[A-Z]/g, " $&"); replace every uppercase character inside a word with a space + the match (matched character)
• Akash Sateesh: hanks for the answer. If the input is "MetadataUSAddressType" I wanted the output as 'Metadata US Address Type'. But I am getting 'Metadata U S Address Type'. Is there any way in regex to achieve this. Basically stream of continuous uppercase characters should be grouped
• Thomas: "continuous uppercase characters should be grouped" You mean Metadata USAddress Type? As here "USA" would be the group of uppercase characters. Just fix the result afterwards: str.replace(/\B[A-Z]/g, " $&").replace(/U S\b/g, v => "US");
• baao: stackoverflow.com/questions/30521224/… --- just replace the underscore with a space

Answer 1

Use regex to replace all upper case with space before and trim to remove first space.

var CamelCaseWord = "MetadataUSAddressType";
alert(CamelCaseWord.replace(/([A-Z])([A-Z])([a-z])|([a-z])([A-Z])/g, '1ドル4ドル 2ドル3ドル5ドル').trim())

• Akash Sateesh: Thanks for the answer. If the input is "MetadataUSAddressType" I wanted the output as 'Metadata US Address Type'. But I am getting 'Metadata U S Address Type'. Is there any way in regex to achieve this. Basically stream of continuous uppercase characters should be grouped.
• Thomas: you can simplify this to replace(/\B([A-Z])([A-Z][a-z])|([a-z])([A-Z])/g, '1ドル3ドル 2ドル4ドル'); and can even get rid of that trim()

Answer 2

i Have Another solution

var str = "MetadataCompanyTotal";
var arr = str.split(/(?=[A-Z])/);
var temp = arr.join(" ");
alert(temp);

can look the code here