issue with php and Json

Question

i cant for the life of me figure out why i cant get this JSON to work

this is how it comes back from api

"{"errorCode":5,"errorDescription":"Unknown account"}" 

i have tried all of the following to get "Unknown account"

$error = $result['errorCode":5,"errorDescription'];
$error = $result['errorCode'];
$error = $result['errorDescription'];

i would be ok even just trying for error code 5, so i can do a check to further the script if account is made or not.

any ideas what i am missing?

• ceejayoz: Show us the code where you fetch the response. Chances are you first have to json_decode it, and it's probably $result->errorCode after that. Use print_r to examine its structure.

Answer 1

try this:

$json = '{"errorCode":5,"errorDescription":"Unknown account"}';
$arr = json_decode($json, true);
$error = $arr['errorDescription'];

In this case you take the json and parse it into the function json_decode of php, wit true value as second parameter It return an associative error where you can get your value by key.

DEMO

• Dynamite Media: omg i had forgotten this "$result = json_decode($cexecute,true);"
• Alessandro Minoccheri: It can be happen, glad to help you! Accept the answer to help other guys with your same problem if this has solved your. Thanks

Answer 2

It's actually a simple matter as there are already builtin functions in PHP for handling JSON. Those are json_encode and json_decode.

$result='{"errorCode":5,"errorDescription":"Unknown account"}';
var_dump($result);
$json=json_decode($result);
var_dump($json);
echo "errorCode={$json->errorCode}<br>";
echo "errorDescription={$json->errorDescription}<br>";

Try the above. Note that json_decode can convert a string into either an object (default) or an associative array.

$json2=json_decode($result,TRUE);
var_dump($json2);
echo "errorCode=".$json2['errorCode']."<br>";
echo "errorDescription=".$json2['errorDescription']."<br>";