I'm trying to return the LARGEST numerical value associated with the 'reduced' array below. Easy enough if there is one value but many have two- as below. I'm using
$reduced_array = $data['rates'][1]['rates'][0];
but this only works in returning the first value. I need to return just the highest value however- so below it would be 8. would something like
if(count($data['rates'][1]['rates']) > 2) {
***return largest value here***
work? I'm just not sure how to perform the asterisked task- maybe a for loop? here is the array.
Array
(
[rates] => Array
(
[0] => Array
(
[name] => Super Reduced
[rates] => Array
(
)
)
[1] => Array
(
[name] => Reduced
[rates] => Array
(
[0] => 5
[1] => 8
)
)
[2] => Array
(
[name] => Standard
[rates] => Array
(
[0] => 23
)
)
[3] => Array
(
[name] => Increased
[rates] => Array
(
)
)
[4] => Array
(
[name] => Parking
[rates] => Array
(
)
)
)
[disclaimer] => Rates data is based on information published by the European Commission, updated 1st January 2017.
)
Thanks for any help
2 Answers 2
You can use max() for that.
$array = array(
"rates" => array(
array(
"name" => "Super Reduced",
"rates" => array()
),
array(
"name" => "Reduced",
"rates" => array(
5,
8
)
)
)
);
echo max($array["rates"][1]["rates"]); // 8
answered May 23, 2017 at 6:51
Tom Udding
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1 Comment
D.Wells
ah thanks, should have checked the php manual sorry, haven't programmed in quite a while.
Easiest solution will be using of max on inner array example:
if(!empty($data['rates'][1]['rates'])) {
$maxvalue = max($data['rates'][1]['rates']);
}
Stephan Vierkant
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lang-php
ratesarray, sort it in descending order, then grab the first value.