Code to find the maximum number of array using recursion always returns the last item in the array

Question

The following code will always write 0. Why is that and how do I fix it?

public static void main(String[] args) 
{
 int[] Array= {5,4,6,3,7,2,8,1,9,0};
 int max=0;
 System.out.println(maximum(Array,Array.length-1,max));
}
public static int maximum(int[] Array,int length,int max)
{
 if (length!=0)
 {
 if(max<Array[length])
 {
 max=Array[length];
 }
 maximum(Array,length-1,max); 
 }
 return max; 
}

• Andreas Løve Selvik: What result are you getting?
• EJoshuaS - Stand with Ukraine: Please elaborate on what you mean by "not working".
• Shahiryar Arif: means it always get 0 in return
• EJoshuaS - Stand with Ukraine: @ShahiryarArif I edited to reflect that, hope that's OK.

Answer 1

When you call maximum recursively, you don't write returned value.

 if (length!=0)
 {
 if(max<Array[length])
 {
 max=Array[length];
 }
 max = maximum(Array,length-1,max); //rewrite max variable
 }
 return max;

EDIT

And need to initialize first max value to Array[0]

int max=Array[0];
System.out.println(maximum(Array,Array.length-1,max));

• EJoshuaS - Stand with Ukraine: @ShahiryarArif Also, it should be length != -1 - right now, if the maximum is the first item in the array, it'll only give the second-highest number.
• Vladimir Parfenov: @ShahiryarArif - I changed my answer