JQuery call function and multiple params from string

Question

If I have a function:

function myfunc(param1, param2, param3) {
 // ...
}

and I have a string:

var myCall = "myfunc(1, 'abc', 'true')"

Is there a way to make the function call using the string and include the params? I don't know the number of parameters in advance. I have tried

var func = myCall.substr(0, myCall.indexOf('('));
var args = myCall.substring(myCall.indexOf('(')+1, myCall.length-1); 
window[func](args.split(','));

but that just calls the function with an array to the first parameter. How do I split the arguments and pass them in with an unknown number of parameters?

• Rahul Singh: stackoverflow.com/questions/1959040/… .This might Help its is like Vargs in Java
• Joe Lissner: you can do eval(myCall)

Answer 1

You can do this using the Function constructor:

function myfunc(param1, param2, param3) {
 console.log(param1, param2, param3);
}
var myCall = "myfunc(1, 'abc', 'true')";
// here the 'myfunc' string indicates the name of a parameter that will
// be passed into the function that new Function is creating.
// i.e., we are going to pass in the myfunc function
// when we actually call myCaller
var myCaller = new Function('myfunc', myCall);
myCaller(myfunc);

Answer 2

You can use .replace() again with RegExp /\(.*/ to replace all characters except for function name, .replace() with RegExp /^\w+(?=\))|[()]/ to remove function name and parenthesis from string, .match() with RegExp /[\w\d]+/g to match digit or word characters, .map() to return digit or word characters within an array, Function.prototype.apply() to pass array to function call

function myfunc(param1, param2, param3) {
 console.log(param1, param2, param3)
}
var myCall = "myfunc(1, 'abc', 'true')";
var fn = myCall.replace(/\(.*/, "");
var params = myCall.replace(/^\w+(?=\))|[()]/, "")
 .match(/[\w\d]+/g).map(function(param) {
 return /\d/.test(param) ? +param : param
 });
window[fn].apply(null, params);