How to check if a string contains all the elements of an array in Javascript

Question

I have a string apple_mango_banana and an array containing [apple,mango].

I want to check if my string contains all of the elements present in the array, if so, I want to show a div with the same ID as my string.

• Nina Scholz: please add your try and have a look here: minimal reproducible example.
• Kevin Kloet: post your code of what you have tried so far, what went wrong and what is the part that you need help with, SO isn't an code fabric that produces code for you.
• Ezio: Use split function to split your string in "_" .This will create a new array and then just check if your array is a subset of this new array. This is how you check if an array is a subset of another array :- stackoverflow.com/questions/14130104/…

Answer 1

Use every() function on the arr and includes() on the str; Every will return true if the passed function is true for all it's items.

var str = 'apple_mango_banana';
var arr = ['apple','banana'];
var isEvery = arr.every(item => str.includes(item));
console.log(isEvery);

• brk: ie wont support, supports start from edge 14
• Suren Srapyan: includes and every are ES6 features

Answer 2

You should use Array.every for such cases.

var s = "apple_mango_banana";
var s1 = "apple_mago_banana";
var fruits = ["apple","mango"];
var allAvailable = fruits.every(function(fruit){
 return s.indexOf(fruit)>-1
});
var allAvailable1 = fruits.every(function(fruit){
 return s1.indexOf(fruit)>-1
});
console.log(allAvailable)
console.log(allAvailable1)

Answer 3

var string="ax_b_c_d";
var array=['b','c','ax','d'];
var arr=string.split("_");
if(array.sort().join("")==arr.sort().join("") && arr.length==array.length)
{
 console.log("match");
 }

• Rajesh Dixit: This will not work if order is changed. Like "banana_apple"