python - to extract a specific string

Question

I have a string like :

 string="(tag, index: develop-AB123-2s), (index: develop-CD123-2s)"

I want to extract only "develop-CD123-2s", i.e. the string that comes after "(index:" and not the one with tag. How do I do in python? Thanks!

Answer 1

^{Warning: I'm not the best at regex}

import re
s='(tag, index: develop-AB123-2s), (index: develop-CD123-2s)'
print re.findall("\\(.*?index: ([^)]+)", s)[1] # 'develop-CD123-2s'

Regex Demo

Alternative regex

re.findall("index: ([^\s)]+)", s)[1]

• donkopotamus: Always useful to use r"..." style strings with regex to avoid needing to use double slashes.
• OneCricketeer: I know. Just a Java habit. Also don't need the (.*?, really.

Answer 2

>>> string.split("), (")[1].split(":")[1].split(")")[0].strip()
'develop-CD123-2s'
>>> 

The first split separates each tuple, then split on : and take the second result

Answer 3

You could do it like this:

string = "(tag, index: develop-AB123-2s), (index: develop-CD123-2s)"
string = string.split('(index:')
string = string[1].strip(')')
print(string)

split the string on (index: and strip off the closing curly bracket

Answer 4

One way is using python regex - positive lookbehind assertion

import re
string = "(tag, index: develop-AB123-2s), (index: develop-CD123-2s)"
re.findall(r"(?<=\(index:) ([^)]+)", string)

This pattern only matches things that start with (index:. You can also look at negative lookbehind assertions to try and match the (tag, part.