Convert string type array to array

Question

I have this:

[s[8] = 5,
 s[4] = 3,
 s[19] = 2,
 s[17] = 8,
 s[16] = 8,
 s[2] = 8,
 s[9] = 7,
 s[1] = 2,
 s[3] = 9,
 s[15] = 7,
 s[11] = 0,
 s[10] = 9,
 s[12] = 3,
 s[18] = 1,
 s[0] = 4,
 s[14] = 5,
 s[7] = 4,
 s[6] = 2,
 s[5] = 7,
 s[13] = 9]

How can I turn this into a python array where I can do for items in x: ?

• Maurice: What kind of data-structure is that? It has the list brackets around it but contains notation to set key and value in a dict?
• Moinuddin Quadri: Are you sure it is the original chunk of code?
• Pavel Gurkov: Is that a string in your code?
• Moinuddin Quadri: Then edit you answer to mentioned it as string. " around each item
• Moinuddin Quadri: What is the expected output? please also mention that

Answer 1

import re
data = """[s[8] = 5,
 s[4] = 3,
 s[19] = 2,
 s[17] = 8,
 s[16] = 8,
 s[2] = 8,
 s[9] = 7,
 s[1] = 2,
 s[3] = 9,
 s[15] = 7,
 s[11] = 0,
 s[10] = 9,
 s[12] = 3,
 s[18] = 1,
 s[0] = 4,
 s[14] = 5,
 s[7] = 4,
 s[6] = 2,
 s[5] = 7,
 s[13] = 9]"""
d = {int(m.group(1)): int(m.group(2)) for m in re.finditer(r"s\[(\d*)\] = (\d*)", data)}
seq = [d.get(x) for x in range(max(d))]
print(seq)
#result: [4, 2, 8, 9, 3, 7, 2, 4, 5, 7, 9, 0, 3, 9, 5, 7, 8, 8, 1]

Answer 2

If you want the array to have the same name that is in the input string, you could use exec. This is not very pythonic, but it works for simple stuff

string = ("[s[8] = 5, s[4] = 3, s[19] = 2,"
 "s[17] = 8, s[16] = 8, s[2] = 8,"
 "s[9] = 7, s[1] = 2, s[3] = 9,"
 "s[15] = 7, s[11] = 0, s[10] = 9,"
 "s[12] = 3, s[18] = 1, s[0] = 4,"
 "s[14] = 5, s[7] = 4, s[6] = 2,"
 "s[5] = 7, s[13] = 9]")
items = [item.rstrip().lstrip() for item in string[1:-1].split(",")]
name = items[0].partition("[")[0]
# Create the array
exec("{} = [None] * {}".format(name, len(items)))
# Populate with the values of the string
for item in items:
 exec(items[0].partition("[")[0] )

This will generate an array named "s" and if there is an index missing it will be initialized as None

Answer 3

Assuming this is one giant string, if you want print s[0] to print 4, then you need to split this up by the commas, then iterate through each item.

inputArray = yourInput[1:-1].replace(' ','').split(',\n\n')
endArray = [0]*20
for item in inputArray:
 endArray[int(item[item.index('[')+1:item.index(']')])]= int(item[item.index('=')+1:])
print endArray

Answer 4

An easy way, although less efficient than Kevin's solution (without using regular expressions), would be the following (where some_array is your string):

sub_list = some_array.split(',')
some_dict = {}
for item in sub_list:
 sanitized_item = item.strip().rstrip().lstrip().replace('=', ':')
 # split item in key val
 k = sanitized_item.split(':')[0].strip()
 v = sanitized_item.split(':')[1].strip()
 if k.startswith('['):
 k = k.replace('[', '')
 if v.endswith(']'):
 v = v.replace(']', '')
 some_dict.update({k: int(v)})
print(some_dict)
print(some_dict['s[9]'])

Output sample:

{'s[5]': 7, 's[16]': 8, 's[0]': 4, 's[9]': 7, 's[2]': 8, 's[3]': 9, 's[10]': 9, 's[15]': 7, 's[6]': 2, 's[7]': 4, 's[14]': 5, 's[19]': 2, 's[17]': 8, 's[4]': 3, 's[12]': 3, 's[11]': 0, 's[13]': 9, 's[18]': 1, 's[1]': 2, 's8]': 5}
7