1

This is my object. Inside the bun array I have 2 objects. I need to access only "oid": 1 and "bid": 1 object details. There is no need to access the second object.

{
 "oid": "1",
 "oname": "Fon",
 "bun": [{
 "bid": "1",
 "bname": "Ets",
 "dep": [{
 "did": "1",
 "dname": "Dptment",
 "pids": [{
 "pid": "1",
 "st": "active"
 }, {
 "pid": "2",
 "st": "active"
 }]
 }]
 }, {
 "bid": "2",
 "bname": "US",
 "description": "unit2",
 "dep": []
 }]
}

How it is possible?

Rory McCrossan
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asked Aug 5, 2016 at 7:05
2
  • 1
    it will be easier if you considered it while building your object Commented Aug 5, 2016 at 7:07
  • post what you tryed or how you created the object. Commented Aug 5, 2016 at 7:11

1 Answer 1

3

One way to achieve is using filter.

let jsObj = {
 "oid": "1",
 "oname": "Fon",
 "bun": [{
 "bid": "1",
 "bname": "Ets",
 "dep": [{
 "did": "1",
 "dname": "Dptment",
 "pids": [{
 "pid": "1",
 "st": "active"
 }, {
 "pid": "2",
 "st": "active"
 }]
 }]
 }, {
 "bid": "2",
 "bname": "US",
 "description": "unit2",
 "dep": []
 }]
};
jsObj.bun.filter((b) => {
 return b.bid == 1
});
answered Aug 5, 2016 at 7:24
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2 Comments

what does "b" means?
@SHERINAS it's a variable name. b in this case is an object from bun array.

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