How do I split the string into an array at an index?

Question

I need to split this string 3:00pm so it ends up as [3:00][pm]. Below is my attempt but it is not correct because the console prints p m.

date = '3:00pm'
var elem = date.slice(date.length-2);

• gen_Eric: .slice() returns a string, not an array. You probably want to use .split() here.

Answer 1

You can get the two different parts with two different slices.

var date = '3:00pm';
var arr = [
 date.slice(0, -2), // first to 2nd from last
 date.slice(-2) // just the last 2
];
console.log(arr);

Answer 2

You can use String.prototype.match() with RegExp /\d+:\d+|\w+/g

var date = "3:00pm"
var elem = date.match(/\d+:\d+|\w+/g);
console.log(elem[0], elem[1])

Answer 3

You could use a regex with positive lookahead.

console.log("3:00pm".split(/(?=[ap]m)/));
console.log("11:55am".split(/(?=[ap]m)/));

• Morteza Tourani: Maybe need to check am too
• Morteza Tourani: That looks great. but may I know why regex and not a simple substring?
• Nina Scholz: @mortezaT, just for fun.
• Morteza Tourani: That's a good point. I've tried that and I think works perfect most of the time.

Answer 4

var date = '3:00pm';
var time = date.substr(0, date.length - 2); // 3:00
var period = date.substr(date.length - 2); // pm
console.log(time);
console.log(period);

• depperm: I'd change the 4 in both spots to date.length-2 or -2 so that 10, 11, and 12 would also work, and remove the 2 in the period line

Answer 5

I believe you want to split not only 3:00pm but also other times. Here is a sample using Regular Expression.

var re=/([0-9:]+)\s*(am|pm)/i;
var ar=[];
'3:00pm'.replace(re,function(m/*whole match ([0-9:]+)\s*(am|pm)*/, pt1/*([0-9:]+)*/, pt2/*(am|pm)*/){
 ar.push(pt1, pt2); //push captures
 return m; //do not change the string
});
console.log(ar); //["3:00","pm"]