I was wondering if it's possible to convert a signed Hexadecimal (negative) to its corresponding decimal value.
1 Answer 1
I assume that you have a hexadecimal value in form of a String.
The method parseInt(String s, int radix) can take a hexadecimal (signed) String and with the proper radix (16) it will parse it to an Integer.
int decimalInt = parseInt(hexaStr, 16);
the solution above only works if you have numbers like -FFAA07BB... if you want the Two's complements you'll have to convert it yourself.
String hex = "F0BDC0";
// First convert the Hex-number into a binary number:
String bin = Integer.toString(Integer.parseInt(hex, 16), 2);
// Now create the complement (make 1's to 0's and vice versa)
String binCompl = bin.replace('0', 'X').replace('1', '0').replace('X', '1');
// Now parse it back to an integer, add 1 and make it negative:
int result = (Integer.parseInt(binCompl, 2) + 1) * -1;
or if you feel like having a one-liner:
int result = (Integer.parseInt(Integer.toString(Integer.parseInt("F0BDC0", 16), 2).replace('0', 'X').replace('1', '0').replace('X', '1'), 2) + 1) * -1;
If the numbers get so big (or small), that an Integer will have an overflow, use Long.toString(...) and Long.parseLong(...) instead.
Integer.parseInt(input,16)will work.