get data from json c#

Question

I have a problem I want to get data from Json, and the data successfully gets from the json to the variable json but when I want to send the data to WeatherData it send me a zero value. I have one class that cald "WeatherData" and I want to send to data from the json (that existing a class "jsonParse") to this class.

jsonParse

 using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Net;
using Newtonsoft.Json;
using Newtonsoft.Json.Linq;
using System.Web.Script.Serialization;
using System.IO;
namespace weather
{
 public class jsonParse : Ijson
 {
 private string urlAdd;
 public jsonParse(string _url)
 {
 if (_url == null)
 {
 //throw exption
 }
 else
 urlAdd = _url;
 }
 public WeatherData parse()
 {
 //string json = new WebClient().DownloadString(urlAdd);
 //var obj = JsonConvert.DeserializeObject<WeatherData>(json);
 //Console.WriteLine(obj.temp);
 // WeatherData m = JsonConvert.DeserializeObject<WeatherData>(json);
 WebClient n = new WebClient();
 var json = n.DownloadString(urlAdd);
 string valueOriginal = Convert.ToString(json);
 WeatherData m = JsonConvert.DeserializeObject<WeatherData>(json);
 Console.WriteLine(m);
 return m;
 }
 }
}

WeatherData

namespace weather
{
 public class WeatherData
 {
 public WeatherData(double _temp, double _minTemp, double _maxTemp )
 {
 temp = _temp;
 minTemp = _minTemp;
 maxTemp = _maxTemp;
 }
 public double temp { get; set; }
 public double minTemp { get; set; }
 public double maxTemp { get; set; }
 public override string ToString()
 {
 return "the weather:" + temp + "minTemp is:" + minTemp + "maxTemp:" + maxTemp;
 }
 }
}

json

{"coord":{"lon":139,"lat":35},
"sys":{"country":"JP","sunrise":1369769524,"sunset":1369821049},
"weather":[{"id":804,"main":"clouds","description":"overcast clouds","icon":"04n"}],
"main":{"temp":289.5,"humidity":89,"pressure":1013,"temp_min":287.04,"temp_max":292.04},
"wind":{"speed":7.31,"deg":187.002},
"rain":{"3h":0},
"clouds":{"all":92},
"dt":1369824698,
"id":1851632,
"name":"Shuzenji",
"cod":200}

Answer 1

If you only care about the weather part of the json, try this -

 var o = (JArray)JObject.Parse(jsonString)["weather"];
 foreach(JToken item in o)
 {
 Console.WriteLine(((JValue)item["id"]).Value);
 Console.WriteLine(((JValue)item["main"]).Value);
 Console.WriteLine(((JValue)item["description"]).Value);
 Console.WriteLine(((JValue)item["icon"]).Value);
 }

• user3488862: And if I want main values - temp, min temp and max temp what do I do?

Answer 2

First object in json is coord, don't see that in your model. You should change your JsonModel to deserialize. From c# class generator:

public class Coord
{
 public int lon { get; set; }
 public int lat { get; set; }
}
public class Sys
{
 public string country { get; set; }
 public int sunrise { get; set; }
 public int sunset { get; set; }
}
public class Weather
{
 public int id { get; set; }
 public string main { get; set; }
 public string description { get; set; }
 public string icon { get; set; }
}
public class Main
{
 public double temp { get; set; }
 public int humidity { get; set; }
 public int pressure { get; set; }
 public double temp_min { get; set; }
 public double temp_max { get; set; }
}
public class Wind
{
 public double speed { get; set; }
 public double deg { get; set; }
}
public class Rain
{
 public int __invalid_name__3h { get; set; }
}
public class Clouds
{
 public int all { get; set; }
}
public class RootObject
{
 public Coord coord { get; set; }
 public Sys sys { get; set; }
 public List<Weather> weather { get; set; }
 public Main main { get; set; }
 public Wind wind { get; set; }
 public Rain rain { get; set; }
 public Clouds clouds { get; set; }
 public int dt { get; set; }
 public int id { get; set; }
 public string name { get; set; }
 public int cod { get; set; }
} 

Where RootObject is your JsonConvert.DeserializeObject(json); So you can change class names as you like.

• Elektryczny: If you want to name properties with your name (not json names) use [JsonProperty"jsonName"] string yourName
• user3488862: do i need to put all of that in "WeatherData"?
• Elektryczny: Well with deserializer i think you have to use following properties to your directed one. Mean if you need "country", you have to add class with "sys". IMO.
• user3488862: It throws an exception.. why is that?
• Elektryczny: What kind of the exception?

Answer 3

Simply you cannot Deserialize a json object to a non-matching class object. So make sure you have a model object that have atleast all the properties that JSON object have.

In this case you would need following classes that are generated from your JSON object:

public class Coord
{
 public int lon { get; set; }
 public int lat { get; set; }
}
public class Sys
{
 public string country { get; set; }
 public int sunrise { get; set; }
 public int sunset { get; set; }
}
public class Weather
{
 public int id { get; set; }
 public string main { get; set; }
 public string description { get; set; }
 public string icon { get; set; }
}
public class Main
{
 public double temp { get; set; }
 public int humidity { get; set; }
 public int pressure { get; set; }
 public double temp_min { get; set; }
 public double temp_max { get; set; }
}
public class Wind
{
 public double speed { get; set; }
 public double deg { get; set; }
}
public class Rain
{
 public int __invalid_name__3h { get; set; }
}
public class Clouds
{
 public int all { get; set; }
}
public class ParentModel
{
 public Coord coord { get; set; }
 public Sys sys { get; set; }
 public List<Weather> weather { get; set; }
 public Main main { get; set; }
 public Wind wind { get; set; }
 public Rain rain { get; set; }
 public Clouds clouds { get; set; }
 public int dt { get; set; }
 public int id { get; set; }
 public string name { get; set; }
 public int cod { get; set; }
}
ParentModel m = JsonConvert.DeserializeObject<ParentModel>(json);

Hope this helps.