Convert PHP Curl To Python

Question

I've been trying to translate some PHP code to Python 3 but can't quite get it to work. In PHP I have the following:

$request = "https://api.example.com/token";
$developerKey = "Basic VVVfdFdfsjkUIHDfdsjYTpMX3JQSDNJKSFQUkxCM0p0WWFpRklh";
$data = array('grant_type'=>'password',
 'username'=>'name',
 'password'=>'pass',
 'scope'=>'2346323');
$cjconn = curl_init($request);
curl_setopt($cjconn, CURLOPT_POST, TRUE);
curl_setopt($cjconn, CURLOPT_HTTPHEADER, array('Authorization: '.$developerKey));
curl_setopt($cjconn, CURLOPT_SSL_VERIFYPEER, FALSE);
curl_setopt($cjconn, CURLOPT_RETURNTRANSFER, TRUE);
curl_setopt($cjconn, CURLOPT_POSTFIELDS,http_build_query($data));
$result = curl_exec($cjconn);
curl_close($cjconn);
$tokens = json_decode($result,true);
$accesstoken = $tokens['access_token'];
echo $accesstoken."\n";

I tried converting it to the following in Python:

import pycurl, json
url = 'https://api.example.com/token'
data = json.dumps({"grant_type":"password",
 "username":"name",
 "password":"pass",
 "scope":"2346323"})
key = 'Basic VVVfdFdfsjkUIHDfdsjYTpMX3JQSDNJKSFQUkxCM0p0WWFpRklh'
c = pycurl.Curl()
c.setopt(pycurl.URL,url)
c.setopt(pycurl.HTTPHEADER,['Authorization: {}'.format(key)])
c.setopt(pycurl.POST,1)
c.setopt(pycurl.POSTFIELDS,data)
c.perform()

But I get the following error:

<faultstring>String index out of range: -1</faultstring>

How can I correct this, or is there a more pythonic solution?

• user2694306: I'm trying to inquire what I am doing wrong. I've provided by attempt at solving a problem that is asked multiple times on SO, so it is clearly not well documented.

Answer 1

If anyone is interested in the solution, I came up with the following which worked:

 def getToken(self):
 """Retrieves the token from provider"""
 #The data to be passed to retrieve the token
 tokenData = {'grant_type':'password',
 'username':TOKENUSERNAME,
 'password':TOKENPASSWORD,
 'scope':TOKENSCOPE}
 #The header parameters
 header_params = {'Authorization':KEY}
 #Make the request for the token
 r = requests.post(TOKENURL,data=tokenData,headers=header_params)
 #Check the status code
 if r.status_code not in [200,203]:
 self.log.logentry("There was an error retrieving the data from Linkshare: {}:{}".format(r.status_code,r.text))
 sys.exit()
 #Extract the data from the response
 data = r.json()
 #Parse the access token
 token = {'token':data['access_token'],
 'type':data['bearer']}
 return token