PHP MySQL value pass to JavaScript

Question

hei,

 $i=0;
 while($row = $result->fetch_assoc()) {
 echo "
 <tr><td>".$row["Number"]."</td><td>".$row["MusikName"]." ".$row["MusikURL"]."</td></tr>";

this part works...it give me -> 1 test1 url1.de 2 test2 url2.de ...

So what I want is to pass the URL to a JavaScript Array...by doing in phpscript

 $urlarray[]=$row["MusikURL"];
 echo $urlarray[$i]; // gives me url1.de url2.de url3.de
 i++; // to fill $urlarray[1] [2] [...] with urls

How do I pass the urls to a JavaScript Array so that I can access to those by javascriptarrayurl[1] javascriptarrayurl[2] (result should be a clear url) ... I got troubles with JSON :c

thanks in advance !!

• RomanPerekhrest: " I got troubles with JSON" - what have you tried with JSON/AJAX?

Answer 1

You can use jQuery and have something like

<?php
$returnArray = array();
while ($row = $result->fetch_assoc()) {
 array_push($returnArray, $row);
}
$jsonArray = json_encode($returnArray);
?>
<script>
$(document).ready(function () {
 var objArray = $.parseJSON("<?php echo $jsonArray; ?>");
 for (var i = 0; i < objArray.length; i++) {
 var row = objArray[i];
 console.log(row);
 // Now here you have access to row.Number row.MusikURL
 }
});

• killertoge: @Ray and Barmar I tried it...didn't work...even if I use JSON.parseJSON... :c paste2.org/09C0JY8w here is the code of my project ... (the first php script and the javascript at the bottom is important ...Could you please help me where the mistakes are ? Anyways thanks for help !
• killertoge: @Ray you can't believe how much helpful you was ...I tried to do this since 1 month ._. btw. I had also to change it to jQuery I think :c

Answer 2

You can use json_encode() to convert a PHP variable to its Javascript literal notation.

<script>
var urlarray = <?php echo json_encode($urlarray); ?>;
</script>