struct Home {
var street:String
var number:Int
}
func getHouse() -> [Home] {
var house = [Home]()
let house1 = Home(street: "Jacob Street", number: 26)
house.append(house1)
let house2 = Home(street: "High Road", number: 58)
house.append(house2)
let house3 = Home(street: "Zebra Close", number: 12)
house.append(house3)
return house
}
var houses = [Home]()
houses = getHouse()
houses.sort({0ドル.street < 1ドル.street })
for i in 0..<houses.count {
print("\(houses[i].street)")
}
I'm trying to sort them alphabetically by street in this example, or possibly by number if needed. They still seem to stay in the order I've put them in rather than being in alphabetical order which i want.
asked Mar 25, 2016 at 9:24
2 Answers 2
The sort
returns a new array, but you're not doing anything with the result. You can either do
let sortedHouses = houses.sort {0ドル.street < 1ドル.street }
or
houses.sortInPlace {0ドル.street < 1ドル.street }
answered Mar 25, 2016 at 9:29
You might use sortInPlace()
,
sort()
returns a new sorted object and leaves the receiver unchanged.
Or
let sortedHouses = houses.sort {0ドル.street < 1ドル.street }
answered Mar 25, 2016 at 9:28
lang-swift