Array prototype clarification

Question

Here's the code:

var o ={};
console.log(Object.getPrototypeOf(o) == Object.prototype); // returns true as expected
console.log(Object.getPrototypeOf(Array) == Array.prototype); // returns false why?

Could someone please clarify the second result?

• tomasbasham: Because Array is not an instantiated instance of an Array

Answer 1

because Array is not an 'array' but the Prototype of Array but with this example :

var a = [];
console.log(Object.getPrototypeOf(a) == Array.prototype);

It works

Answer 2

Try

var a=[];
console.log(Object.getPrototypeOf(a) == Array.prototype); 

You're using the Array type itself, instead of an instance of it.