Where I can find jquery.param implementation code?

Question

I would like to know where I can find the implementation code for jquery.param.

Answer 1

/src/ajax.js

Answer 2

Here is the source directly from jQuery (MIT license):

jQuery.param = function( a, traditional ) {
 var prefix,
 s = [],
 add = function( key, value ) {
 // If value is a function, invoke it and return its value
 value = jQuery.isFunction( value ) ? value() : ( value == null ? "" : value );
 s[ s.length ] = encodeURIComponent( key ) + "=" + encodeURIComponent( value );
 };
 // Set traditional to true for jQuery <= 1.3.2 behavior.
 if ( traditional === undefined ) {
 traditional = jQuery.ajaxSettings && jQuery.ajaxSettings.traditional;
 }
 // If an array was passed in, assume that it is an array of form elements.
 if ( jQuery.isArray( a ) || ( a.jquery && !jQuery.isPlainObject( a ) ) ) {
 // Serialize the form elements
 jQuery.each( a, function() {
 add( this.name, this.value );
 });
 } else {
 // If traditional, encode the "old" way (the way 1.3.2 or older
 // did it), otherwise encode params recursively.
 for ( prefix in a ) {
 buildParams( prefix, a[ prefix ], traditional, add );
 }
 }
 // Return the resulting serialization
 return s.join( "&" ).replace( r20, "+" );
};

• Nate Barbettini: Welcome to Stack Overflow! Code-only answers are discouraged. Can you edit your post to describe where you got this code, perhaps?
• Chubas: This is probably a correct answer, however, the lack of a source means that 1) no context is provided and 2) is very susceptible to be outdated. A link and a little explanation would improve this answer a lot
• Daniel Imms: Please explain where you got the source from in the future, simply pasting the code here and claiming it as your own is against the jQuery license. I added proper attribution.

Answer 3

In case anyone else stumbles across this, it's in src/serialize.js now https://github.com/jquery/jquery/blob/master/src/serialize.js