php weird undefined offset error

Question

In my php applicaiton I have the following code:

try {
 $ordersIngredients[$userIngredient->getId()][$day] += $quantity;
} catch (\Exception $e) {
 ~r(array(
 $ordersIngredients[$userIngredient->getId()],
 $day,
 array_key_exists($day, $ordersIngredients[$userIngredient->getId()]),
 $e->getMessage()
 ));
}

The r() function prints the following:

array(4)
 0 => array(4)
 0 => 0.9
 1 => null
 2 => null
 3 => 1
 )
 1 => 3
 2 => true
 3 => Notice: Undefined offset: 3
)

How can I have an error on un undefined offset when the offset actually exists given the dump of the array and array_key_exists ?

• phpisuber01: Side note: How do you have a function name that starts with ~?
• AbraCadaver: @phpisuber01: Not part of the name php.net/manual/en/language.operators.bitwise.php
• Sébastien: ~r (REF) is a library for dumping stuff
• gen_Eric: How is your catch catching this? It's a notice not an exception/error.
• Barmar: @RocketHazmat Maybe he's defined a custom error handler, as in stackoverflow.com/questions/5373780/…

Answer 1

The issue here is that you were trying to append to a value that did not exist in the array.

$ordersIngredients[$userIngredient->getId()][$day] += $quantity;

This is the same as writing:

$ordersIngredients[$userIngredient->getId()][$day] = 
 $ordersIngredients[$userIngredient->getId()][$day] + $quantity;

So, what's happening is that PHP is trying to read the value at index 3, but it can't. That's what causes your notice. Since it's only a notice, PHP treats the undefined index as null and keeps going. It then adds null + $quantity to your array.

After finishing the line, it moves into your error handler and then to your catch block.