How to check if an Array contains a particular word in a String and get it?

Question

I have a String[] and an input String:

String[] ArrayEx = new String[1];
String textInput = "a whole bunch of words"

What I want to do is check if the String contains a word present in the Array, like this.

Ex: textInput = "for example" and ArrayEx[0] = "example"

I know about this method:

Arrays.asList(yourArray).contains(yourValue)

but it checks the full String right? How do I check if the String contains a particular word present in the Array. Even if it is from an ArrayList I have no problem.

Also if yes, can I get that word from the String[]? i.e., in the above case get the String "example".

EDIT:

public void searchNearestPlace(String v2txt)
{
 Log.e("TAG", "Started");
 v2txt = v2txt.toLowerCase();
 String[] places = {"accounting, airport, amusement_park, aquarium, art_gallery, atm, bakery, bank, bar, beauty_salon, bicycle_store, book_store, bowling_alley, bus_station, cafe, campground, car_dealer, car_rental, car_repair, car_wash, casino, cemetery, church, city_hall, clothing_store, convenience_store, courthouse, dentist, department_store, doctor, electrician, electronics_store, embassy, establishment, finance, fire_station, florist, food, funeral_home, furniture_store, gas_station, general_contractor, grocery_or_supermarket, gym, hair_care, hardware_store, health, hindu_temple, home_goods_store, hospital, insurance_agency, jewelry_store, laundry, lawyer, library, liquor_store, local_government_office, locksmith, lodging, meal_delivery, meal_takeaway, mosque, movie_rental, movie_theater, moving_company, museum, night_club, painter, park, parking, pet_store, pharmacy, physiotherapist, place_of_worship, plumber, police, post_office, real_estate_agency, restaurant, roofing_contractor, rv_park, school, shoe_store, shopping_mall, spa, stadium, storage, store, subway_station, synagogue, taxi_stand, train_station, travel_agency, university, veterinary_care, zoo"};
 int index;
 for(int i = 0; i<= places.length - 1; i++)
 {
 Log.e("TAG","for");
 if(v2txt.contains(places[i]))
 {
 Log.e("TAG", "sensed?!");
 index = i;
 }
}

Say v2txt was "awesome airport" the sensed Log never does appear even though all other logs indicate it working

Edit2:

I am so embarrassed that I made such a dunder head mistake. My array is declared wrongly. There should be a " before every ,. I am such a big idiot! Sorry will change it and let you know.

• KISHORE_ZE: Guys why the down votes. Is there something wrong. Please do let me know also.
• bcsb1001: Start with docs.oracle.com/javase/7/docs/api/java/lang/…
• folkol: Is the array of one word strings only, or can the array entries have full sentences as well?
• KISHORE_ZE: Array one or 2 words. And String sentences
• folkol: And you want to know if the sentence contains any of the words from the array, or just the (1 or 2 word) phrases from the array?

Answer 1

First of all it has nothing to do with android

Second the solution

boolean flag = false;
String textInput = "for example";
int index = 0;
String[] yourArray = {"ak", "example"};
for (int i = 0; i <= yourArray.length - 1; i++) {
 if (textInput.contains(yourArray[i])) {
 flag = true;
 index = i;
 }
}
if (flag) 
 System.out.println("found at index " + index);
else 
 System.out.println("not found ");

DEMO

EDIT :

Change your array to

String[] places = {"accounting", "airport", "amusement_park" };

and so on with other values with your array declaration it has one index.

• KISHORE_ZE: But doesn't this check the full String?
• KISHORE_ZE: And 2 sorry this was for an android project but you are right this code does not relate to android. I'll remove it.
• KISHORE_ZE: Thanks for the edit but still won't it check the full String instead of one word by one.
• singhakash: @KISHORE_ZE this code take the string at each index of array and finds if it is a substring of textInput is that what you wanted? added a demo also
• KISHORE_ZE: It worked. I am sorry all of them were correct but since I could give only one correct I gave it to the guy who first answered. Sorry. But I gave everyone one up vote.

Answer 2

you can split your string and get array of words

txArray = textInput.split(" ");

then for each element in txArray check if

Arrays.asList(ArrayEx).contains(txArray[i])

• KISHORE_ZE: How would I get them into an array. And how would I get the word in the array.
• krzydyn: txArray = textInput.split(" "); creates array of words
• KISHORE_ZE: It works but it's kinda complex. Like I int i will be the new arrays lenght or it gives a npe. But
• KISHORE_ZE: I am sorry all of them were correct but since I could give only one correct I gave it to the guy who first answered. Sorry. But I gave everyone one up vote.

Answer 3

txArray = "Hello I'm your String";
String[] splitStr = txArray.split(" ");
int i=0;
while(splitStr[i]){
if(Arrays.asList(ArrayEx).contains(txArray[i])){
System.out.println("FOUND");
}
i++;
}

• KISHORE_ZE: I am sorry all of them were correct but since I could give only one correct I gave it to the guy who first answered. Sorry. But I gave everyone one up vote and BTW it's a duplicate. Still no problem 😉

Answer 4

You can use Java - Regular Expressions.

A regular expression is a special sequence of characters that helps you match or find other strings or sets of strings, using a specialized syntax held in a pattern. They can be used to search, edit, or manipulate text and data.

import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Testing {
 public static void main(String[] args) {
 String textInput = "for example";
 String[] arrayEx = new String[1];
 arrayEx[0] = "example";
 Pattern p = Pattern.compile(arrayEx[0]);
 Matcher m = p.matcher(textInput);
 boolean matchedFoundStatus = false;
 while (m.find()) {
 matchedFoundStatus = true;
 }
 System.out.println("matchedFoundStatus:" + matchedFoundStatus);
 }
}

• KISHORE_ZE: Thanks for the answer. I am sorry all of them were correct but since I could give only one correct I gave it to the guy who first answered. Sorry. But I gave everyone one up vote.

Answer 5

Try this;

Sting text2check = "Your Name":

for(int t = 0; t < array.length; t++)
{
if (text2check.equals(array[t])
// Process it Here
break;
}

• KISHORE_ZE: There is no to String available on an array
• Want2bExpert: I will edit my answer, i was trying to say the return value of array is string because you to store string in it. Alternatively use String.valueof(array[t]) if it is not String already.
• KISHORE_ZE: Ok understood. No need of to String and it's working now.
• KISHORE_ZE: I am sorry all of them were correct but since I could give only one correct I gave it to the guy who first answered. Sorry. But I gave everyone one up vote.
• KISHORE_ZE: Also for my purpose .equals should probably be .contains

Answer 6

"How do I check if the String contains a particular word present in the Array?" is the same thing as Is there an element in the array, for which the input string contains this element

Java 8

String[] words = { "example", "hello world" };
String input = "a whole bunch of words";
Arrays.stream(words).anyMatch(input::contains);

(The matching words can also be extracted, if needed:)

Arrays.stream(words)
 .filter(input::contains)
 .toArray();

If you are stuck with Java 7, you will have to re-implement "anyMatch" and "filter" yourself:

Java 7

boolean anyMatch(String[] words, String input) {
 for(String s : words)
 if(input.contains(s))
 return true;
 return false;
}
List<String> filter(String[] words, String input) {
 List<String> matches = new ArrayList<>();
 for(String s : words)
 if(input.contains(s))
 matches.add(s);
 return matches;
}

• KISHORE_ZE: Thanks. But it's answered now. I am sorry all of them were correct but since I could give only one correct I gave it to the guy who first answered. Sorry. But I gave everyone one up vote.
• folkol: Don't be sorry :) Just select the answer that helped you, and good luck with your program!
• KISHORE_ZE: Ok thanks. Wish I could mark multiple answers as correct though.
• folkol: All upvoted answers will be "correct" in some sense, the "selected" answer is just so that people with the same problem as you can find "any solution" at a glance.
• KISHORE_ZE: Ya but still for you guys 15 points out right. I feel bad I can't give you them to you guys even after all the effort you guys put into it.

Answer 7

This will take an String array, and search through all the strings looking for a specific char sequence found in a string. Also, native Android apps are programmed in the Java language. You might find it beneficial to read up more on Strings.

String [] stringArray = new String[5];
//populate your array
String inputText = "abc";
for(int i = 0; i < stringArray.length; i++){
 if(inputText.contains(stringArray[i]){
 //Do something
 }
}

• KISHORE_ZE: I am sorry all of them were correct but since I could give only one correct I gave it to the guy who first answered. Sorry. But I gave everyone one up vote.
• KISHORE_ZE: Also for my purpose stringArray[i].contains(inputText) should probably be inputText.contains(stringArray[i])
• Turtle: Yes, I see that upon re reading the question. I thought you wanted the answer the other way around. My mistake
• KISHORE_ZE: Hey no problem. It was almost correct want it and also you took the effort to help others right? No problem
• KISHORE_ZE: Yes it does. Thank you