Converting string to json object using json.simple

Question

I am using org.json.simple.JSONObject. I want to convert string to Json object.

String value=request.getParameter("savepos");
JSONObject jsonObject = (JSONObject) JSONValue.parse(value);

It doesn't work. Why?

• Jon Skeet: "But no success" doesn't tell us any information about the failure mode. What's the value of value? What happens with the code you've tried?
• Tank: Is "savepos" properly formatted JSON and !null?
• Ghost Rider: how to convert from Java object ( Sample s = new Sample()) to JSON string?
• Anzar Ansari: stackoverflow.com/questions/5245840/…

Answer 1

Try this:

JSONParser parser = new JSONParser();
JSONObject json = (JSONObject) parser.parse(stringToParse);

• Menuka Ishan: Since There are Multiple JSONParser libraries, Library name would be helpful
• Ghost Rider: how to convert from Java object ( Sample s = new Sample()) to JSON string?
• Mukit09: here json.simple Parser is used, I guess.
• ado387: @MenukaIshan You can import json-simple's parser from org.json.simple.parser.JSONParser
• barrypicker: Why are all the examples so limited and incomplete? No import namespace included, the method seems to require a try-catch block, no example how to transfer back to string... Thanks for this idea, but it could be so much more helpful if you simply completed the thought...

Answer 2

JSONParser parser = new JSONParser();
JSONObject json = (JSONObject) parser.parse(value);

should do the work.

Answer 3

Converting String to Json Object by using org.json.simple.JSONObject

private static JSONObject createJSONObject(String jsonString){
 JSONObject jsonObject=new JSONObject();
 JSONParser jsonParser=new JSONParser();
 if ((jsonString != null) && !(jsonString.isEmpty())) {
 try {
 jsonObject=(JSONObject) jsonParser.parse(jsonString);
 } catch (org.json.simple.parser.ParseException e) {
 e.printStackTrace();
 }
 }
 return jsonObject;
}

Answer 4

In the newer com.github.cliftonlabs.json_simple the code is the following:

JsonObject obj = Jsoner.deserialize(responseString, new JsonObject());

As documented on the project's API docs