function with parameters as an array with objects javascript

Question

I had a problem where i sa feeding an Function with an array with objects inside.

var func = function (){
 var feeded = //here is my problem
 /*some code/*
}
var itemArray = [{"stat":49,"amount":156},{"stat":40,"amount":108},{"stat":5,"amount":207},{"stat":7,"amount":311}] //just an exsample
var answare = func(itemArray)

How do i med the variable feeded the same as itemArray, so i can use the methods for arrays on feeded?

I have tried useing:

var feeded = [].slice.call(arguments)

and

var feeded = arguments

I could not use a for loop and then get the stat and amount inside. (i am not needing to close lines as it is not needed in google script

• Amadan: You are overthinking it. var func = function(feeded) { ... } should work for you, given that you are invoking it with func(itemArray). Alternately, var func = function() { var feeded = arguments[0]; ... }, if you really, really hate that parameter there. It would be a different matter if you invoked func.apply(this, itemArray), but there is no reason to.
• Felix Kling: You should read a tutorial about functions, such as developer.mozilla.org/en-US/docs/Web/JavaScript/Guide/Functions or eloquentjavascript.net/03_functions.html
• Meltinglava: if you say `var func = funtion(feeded), feeded is only the first object, as all that is feeded to the funtion becomes an array, you juts name the first object inside the array
• Amadan: @MeltinglavaOutland: As I said, as long as you are passing one argument, like func(itemArray), you are only getting a single argument in the function. You don't need to access arguments unless you want to handle the syntax func(), func(item), func(item, item)... and not func(itemArray).

Answer 1

You need to make the function accept a parameter. Simply put a suitable name for the parameter in the parentheses of your the function declaration like this:

var func = function(items){
 [...]
}

Inside the function, you can access the parameter by simply using it's name. In your case it would be like this:

var func = function(items){
 var feeded = items;
}

You can read more about functions in javascript here

Answer 2

Actually you can iterate those with a for Loop

var func = function (){
 var feeded = arguments;
 console.log(arguments);
 for(var i = 0; i < feeded[0].length; i++)
 console.log(feeded[0][i].stat);
}
var itemArray = [{"stat":49,"amount":156},{"stat":40,"amount":108},{"stat":5,"amount":207},{"stat":7,"amount":311}] //just an exsample
var answare = func(itemArray)

You might just have forgot to access arguments[0] instead of arguments

• ozil: what is arguments ??
• Iwan1993: arguments is an array of arguments given, but not defined in parameters of function e.g. func('a', 'b'); would have arguments[0] == 'a' and arguments[1] == 'b'
• ozil: arguments is a key world?/
• David Knipe: arguments isn't quite an array, but [].slice.call(arguments) will return its contents as an array.
• Meltinglava: So it is an array inside an array. That explains why i got arguments.length = 1.

Answer 3

Try:

var func = function (){
 var feeded = arguments; //is itemArray Array
 console.log(feeded)
 /*some code*/
}
var itemArray = [{"stat":49,"amount":156},{"stat":40,"amount":108},{"stat":5,"amount":207},{"stat":7,"amount":311}] //just an exsample
var answare = func.apply(null, itemArray)

• ozil: what is arguments ??
• Walter Chapilliquen - wZVanG: arguments = itemArray[]