Remove specific elements from array Javascript/jquery

Question

Currently I have an array like this:

var list = new Array([
 {id: 0, content: "zero", group: 1},
 {id: 1, content: "one", group: 2},
 {id: 2, content: "two", group: 1},
 {id: 3, content: "three", group: 1},
 {id: 4, content: "four", group: 3},
 ]);

How can I remove the entries where group == 1 using javascript or Jquery?

• adeneo: That is a strange way to create an array, you end up with an array containing the array containing the objects.
• joews: It's a very... Java... way to create an array.
• try-catch-finally: You might take a look at splice(). Note: you have to iterate the list using a loop but care for a correct counter when removin elements.

Answer 1

Change the array in the following way:

var list = [
 {id: 0, content: "zero", group: 1},
 {id: 1, content: "one", group: 2},
 {id: 2, content: "two", group: 1},
 {id: 3, content: "three", group: 1},
 {id: 4, content: "four", group: 3},
];

otherwise you will end up as an array containing another array. After that you can filter the array on the following way:

var filtered = list.filter(function(item) {
 return item.group !== 1
});
console.log(filtered);

Answer 2

in javascript:

 list =list.filter(function(item){
 return item.group!=1
 })

Answer 3

You don't need to use new Array - your code creates an array with one element, which is itself an array with five elements. You should just use an Array literal:

var list = [
 {id: 0, content: "zero", group: 1},
 {id: 1, content: "one", group: 2},
 {id: 2, content: "two", group: 1},
 {id: 3, content: "three", group: 1},
 {id: 4, content: "four", group: 3},
]

Once you've done that, you can use Array.prototype.filter:

var filtered = list.filter(function(item) {
 return item.group !== 1;
})

If you do mean to build a 2D array you could still use filter:

var filtered = [list[0].filter(function(item) {
 return item.group !== 1;
})]