Debugging Python code

Question

After a few days I still cannot figure out how to make this work on python (not an experienced programmer). Here it is the code pasted and at the bottom, the expected result:

color_list = ["red", "blue", "orange", "green"]
secuence = ["color", "price"]
car_list = []
def create_list(color_list, secuence, car_list):
 for num in range(len(color_list)):
 car_list.append = dict.fromkeys(secuence)
 car_list[%s]['color'] = color_list[%s] %num 
 return car_list

This is the result I want to achieve:

>> car_list
[{'color': 'red', 'price': None},{'color': 'blue', 'price': None},{'color': 'orange', 'price': None},{'color': 'green', 'price': None}]

Answer 1

You can do it all in one line for this particular scenario, assuming that 'color' and 'price' are constants.

car_list = [{'color': color, 'price': None} for color in color_list]

See list comprehension - it's a powerful tool.

---

If you also had a list of prices, price_list, you could do something similar:

car_list = [{'color': color, 'price': price} for color, price in zip(color_list, price_list)]

See the built in function zip().

---

If the strings 'color' and 'price' are unknown at the time of execution (which I think is unlikely), you could do something similar to the following

car_list = [{secuence[0]: color, secuence[1]: price} for color, price in zip(color_list, price_list)]

• Blender User: what if I also wanted to asign something to 'price'? (what I want to asign to it is in a different list)
• enigma: @BlenderUser the second section of my answer should answer that for you. If I have misunderstood what you mean, could you clarify?
• Blender User: Yes, that's exactly!! Srry

Answer 2

Try the following I'm not sure your can use key addressing not but here I have used it.

def create_list(color_list, secuence, car_list): 
 for each in color_list:
 tmp = dict.fromkeys(secuence)
 tmp['color'] = each
 car_list.append(tmp)
 return car_list