nested for loop

Question

Just learning Python and trying to do a nested for loop. What I'd like to do in the end is place a bunch of email addresses in a file and have this script find the info, like the sending IP of mail ID. For now i'm testing it on my /var/log/auth.log file

Here is my code so far:

#!/usr/bin/python
# this section puts emails from file(SpamEmail) in to a array(array)
in_file = open("testFile", "r")
array = in_file.readlines()
in_file.close()
# this section opens and reads the target file, in this case 'auth.log'
log = open("/var/log/auth.log", "r")
auth = log.readlines()
for email in array:
 print "Searching for " +email,
 for line in auth:
 if line.find(email) > -1:
 about = line.split()
 print about[0],
 print

Inside 'testfile' I have the word 'disconnect' cause I know it's in the auth.log file. It just doesn't find the word 'disconnect'. In the line of "if line.find(email)> -1:" i can replace email and put "disconnect" the scripts finds it fine.

Any idea? Thanks in advance. Gary

• Justin Ardini: What's the output you get? Do you get "Searching for disconnect"?

Answer 1

I'm not quite sure what you're asking, but an obvious problem with the above is that readlines() returns a list of lines, each of which (except potentially the last) will have a \n line terminator. So email will have a newline at the end of it, so won't be found in line unless it's right at the end.

So perhaps something like:

with open('testFile', 'r') as f:
 emails= f.read().split('\n')
with open('/var/log/auth.log', 'r') as f:
 lines= f.read().split('\n')
for email in emails:
 for linei, line in enumerate(lines):
 if email in line:
 print 'Line %d, found:' % linei
 print line

Answer 2

I got it. I needed to add from __future__ import with_statement.