I'm using array_add($array, 'key', 'value'); to create the data structure.
foreach ($archives as $archive){
$results = array_add($results, $archive->year,
array($archive->month => array('name' => $archive->month_name)));
}
If i json_encode()the $results i get this output:
{
2015: {
02: {name:'February'}
}
}
But i want something like:
{
2015: {
02: {name:'February'},
01: {name:'January'}
}
}
And of course this should works for different years too.
asked Feb 10, 2015 at 15:13
Christopher
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2 Answers 2
In response to my comments - here's what I'd do:
foreach ($archives as $archive)
{
if (!isset($results[$archive->year]))
{//if the year-key doesn't exist yet, create it
//if it already exists, this part will be skipped
$results[$archive->year] = array();
}
//then add the values
$results[$archive->year][$archive->month] = array(
'name' => $archive->month_name
);
}
That's all there is to it, no need for a home-made function or anything like that
answered Feb 10, 2015 at 15:35
Elias Van Ootegem
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Comments
How about array_push($array, 'key', 'value');
answered Feb 10, 2015 at 15:19
Bharat Paudyal
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1 Comment
Elias Van Ootegem
That won't work at all, that'll push
'key' and 'value' as separate values onto $array consecutively see the manual lang-php
array_addisn't a core php function, can you show the function aswell? Besides$resultsis overwritten in every iteration.array_add), when you could just write$results[$archive->year] = array($archive->month => array('name' => $archive->month_name));? Oh, and could it be that "January" isn't int$resultsbecause it's not in the$archivesto begin with? check those values, too$results[$archive->year]doesn't already exist, if it does, your code currently reassigns it (overwriting the array that it already holds), I'll post an answer