I am trying return a JSON response from a controller in Symfony 2. Form example, in Spring MVC I can get a JSON response with @ResponseBody annotattion. I want get a JSON response, no mtter if it is a JSON Array or a Json Object, then, manipulate it with javascript in the view.
I try the next code:
/**
* @Route(
* "/drop/getCategory/",
* name="getCategory"
* )
* @Method("GET")
*/
public function getAllCategoryAction() {
$categorias = $this->getDoctrine()
->getRepository('AppBundle:Categoria')
->findAll();
$response = new JsonResponse();
$response->setData($categorias);
$response->headers->set('Content-Type', 'application/json');
return $response;
}
But I get [{},{}]
as Response in the browser. I try with $response = new Response(json_encode($categorias));
too, but I get the same result.
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Did you try 'return new JSONResponse($data);'?Naftali– Naftali2015年01月28日 11:54:48 +00:00Commented Jan 28, 2015 at 11:54
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$categorias is an object. but setData expects an array.Juergen Schulze– Juergen Schulze2023年01月24日 11:58:04 +00:00Commented Jan 24, 2023 at 11:58
7 Answers 7
I think the @darkangelo answer need explainations.
The findAll()
method return a collection of objects.
$categorias = $this->getDoctrine()
->getRepository('AppBundle:Categoria')
->findAll();
To build your response, you have to add all getters of your entities to your response like :
$arrayCollection = array();
foreach($categorias as $item) {
$arrayCollection[] = array(
'id' => $item->getId(),
// ... Same for each property you want
);
}
return new JsonResponse($arrayCollection);
Use QueryBuilder
allows you to return results as arrays containing all properties :
$em = $this->getDoctrine()->getManager();
$query = $em->createQuery(
'SELECT c
FROM AppBundle:Categoria c'
);
$categorias = $query->getArrayResult();
return new JsonResponse($categorias);
The getArrayResult()
avoids need of getters.
You need to do this (based on previous answer):
public function getAllCategoryAction() {
$em = $this->getDoctrine()->getManager();
$query = $em->createQuery(
'SELECT c
FROM AppBundle:Categoria c'
);
$categorias = $query->getArrayResult();
return new JsonResponse($categorias);
}
It works perfect with any Query that Doctrine returns as array.
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13You can improve your answer by using
JsonResponse
instead ofResponse
. This will avoid duplicate uses ofjson_encode
and custom headers.chalasr– chalasr2016年01月03日 13:51:28 +00:00Commented Jan 3, 2016 at 13:51
/**
* @Route("/api/list", name="list")
*/
public function getList(SerializerInterface $serializer, SomeRepository $repo): JsonResponse
{
$models = $repo->findAll();
$data = $serializer->serialize($models, JsonEncoder::FORMAT);
return new JsonResponse($data, Response::HTTP_OK, [], true);
}
-
as explain at symfony.com/doc/current/serializer.html add
use Symfony\Component\Serializer\SerializerInterface;
, I should add alsouse Symfony\Component\HttpFoundation\JsonResponse;
bcag2– bcag22022年03月09日 14:48:41 +00:00Commented Mar 9, 2022 at 14:48
Following the best practices, I managed to do it the following way:
public function index(CityRepository $cityRepository,
SerializerInterface $serializer): Response
Injecting repository & serializer.
$cities = $cityRepository->findAll();
Retrieving an array of objects.
$data = $serializer->serialize($cities, 'json');
Serializing the data into a JSON string.
return new JsonResponse($data, 200, [], true);
Passing the JSON string to JsonResponse
.
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I get very ugly object "{\u0022id\u0022:105,\u0022name\u0022:\u00223..." how to fix it ?Artur O– Artur O2020年05月06日 18:41:57 +00:00Commented May 6, 2020 at 18:41
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@ArturO The serializer in this example returns a JSON string; check that the
JsonResponse
has the last parameter set to true.Jan Bodnar– Jan Bodnar2020年05月06日 20:12:46 +00:00Commented May 6, 2020 at 20:12
You need to change your code this way:
/**
* @Route(
* "/drop/getCategory/",
* name="getCategory"
* )
* @Method("GET")
*/
public function getAllCategoryAction() {
$categorias = $this->getDoctrine()
->getRepository('AppBundle:Categoria')
->findAll();
$categorias = $this->get('serializer')->serialize($categorias, 'json');
$response = new Response($categorias);
$response->headers->set('Content-Type', 'application/json');
return $response;
}
If the serializer
service is not enabled, you have to enable it in app/config/config.yml
:
framework:
# ...
serializer:
enabled: true
For more advanced options for serialization, you can install JMSSerializerBundle
-
I get a 500 error: You have requested a non-existent service "serializer".Giancarlo Ventura Granados– Giancarlo Ventura Granados2015年01月25日 22:00:36 +00:00Commented Jan 25, 2015 at 22:00
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You have to enable first the serializer service. In app/config/config.yml add this:
framework: # ... serializer: enabled: true
Alexandru Furculita– Alexandru Furculita2015年01月25日 22:04:47 +00:00Commented Jan 25, 2015 at 22:04 -
I get the solution: $categorias = $query->getArrayResult(); //$response->headers->set('Content-Type', 'application/json'); //return $response; //return $this->render('AppBundle:Front:test.html.twig', array('otra' => $otra)); return new Response(json_encode($categorias), 200);Giancarlo Ventura Granados– Giancarlo Ventura Granados2015年01月25日 22:28:43 +00:00Commented Jan 25, 2015 at 22:28
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That's a good solution too. Didn't work using the
serializer
service? I find to be a better practice to use a serializerAlexandru Furculita– Alexandru Furculita2015年01月25日 22:35:55 +00:00Commented Jan 25, 2015 at 22:35
Looks like you are trying to put into response a collection. For that you need to setup serializer (or retrieve data as an array).
Look at this doc pages: http://symfony.com/doc/current/components/http_foundation/introduction.html#creating-a-json-response
and
I suggest the following solution:
/**
* @Route(
* "/drop/getCategory/",
* name="getCategory"
* )
* @Method("GET")
*/
public function getAllCategoryAction() {
$em = $this->getDoctrine()->getManager();
$query = $em->createQuery(
'SELECT c
FROM AppBundle:Categoria c'
);
$categorias = $query->getArrayResult();
return new Response(json_encode($categorias), 200);
}
-
2You should probably use newJsonResponse like you did in your question.Cerad– Cerad2015年01月25日 22:39:14 +00:00Commented Jan 25, 2015 at 22:39