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I have four bytes from a raw socket: value=0xc0ff00c0. Using struct with a format of L (or I for that matter) to unpack 

struct.unpack("=L",value)

I get 3221290944. Using 

int(hexlify(value),16)

I get 3237937344. The latter is correct. I have not noticed this with other format specifiers so I assume it must have something to do with the larger integral structures like Long. Has anyone else noticed this? Thanks

asked Jan 13, 2015 at 10:20
2
  • Is the value packed with python? Commented Jan 13, 2015 at 10:25
  • Also using struct.unpack("!L",value) or struct.unpack(">L",value). Yields the correct result. ! means network format. So I'm guessing that is what you need. Commented Jan 13, 2015 at 10:29

1 Answer 1

2

You should unpack with:

struct.unpack("!L",value)

Since data is sent over network you should unpack using network ordering - !

Source

answered Jan 13, 2015 at 10:30
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