1

I have a simple Java REST webservice - 

@GET
 @Path("/get1")
 @Produces(MediaType.APPLICATION_JSON)
 @Consumes(MediaType.APPLICATION_JSON)
 public Status getstudent(Track track) {
 System.out.println("GET1 title = " + track.getTitle());
 System.out.println("GET1 singer = " + track.getSinger());
 Status status = new Status();
 status.setStatus_flag("success");
 return status;
 }

Track

public class Track {
 String title;
 String singer;
 public String getTitle() {
 return title;
 }
 public void setTitle(String title) {
 this.title = title;
 }
 public String getSinger() {
 return singer;
 }
 public void setSinger(String singer) {
 this.singer = singer;
 }
 @Override
 public String toString() {
 return "Track [title=" + title + ", singer=" + singer + "]";
 }
}

Python request module:- 

import requests
title = {"title":"Best Songs","singer":"lucky"}
r = requests.get("http://localhost:8080/StudentService/rest/insert/get1",data=title)
print r.content

Error

<html><head></head><body>
<h1>HTTP Status 415 - Unsupported Media Type</h1>
<HR size="1" noshade="noshade">
<p><b>type</b> Status report</p>
<p><b>message</b> <u>Unsupported Media Type</u></p>
<p><b>description</b> 
 <u>The server refused this request because the request entity is 
 in a format not supported by the requested resource for the requested 
 method.
 </u>
</p>
<HR size="1" noshade="noshade"><h3>Apache Tomcat/6.0.41</h3>
</body></html>

Is there a way to create the entity object and send it?

asked Oct 30, 2014 at 22:36

2 Answers 2

1

You need to use the params to send URL parameters; you are trying to send a request body instead.

You need to alter your service to accept form parameters:

@GET
@Path("/get1")
@Produces(MediaType.APPLICATION_JSON)
@Consumes(MediaType.APPLICATION_FORM_URLENCODED)
public Status getstudent(
 @FormParam("title") String title,
 @FormParam("singer") String sing) {
 System.out.println("GET1 title = " + title);
 System.out.println("GET1 singer = " + singer);
 Status status = new Status();
 status.setStatus_flag("success");
 return status;
}

Now you can send URL-encoded parameters:

params = {"title": "Best Songs", "singer": "lucky"}
r = requests.get(
 "http://localhost:8080/StudentService/rest/insert/get1",
 params=params)
answered Oct 30, 2014 at 22:40
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4 Comments

@user1050619: Does your Java service expect a JSON request then?
Yes, it expects a JSON request now..I have edited the web method @consumes(to accept only JSON request) now...Still not working
@user1050619: I'm not familiar with Java REST servers; no idea if that would require a POST request instead.
@user1050619: looking at vogella.com/tutorials/REST/article.html you should really use @Consumes(MediaType.APPLICATION_FORM_URLENCODED) and @FormParam to specify the title and singer.
0

Just add content-type and accept in headers. Like:

headers = {"Content-Type": "application/json", "Accept": "application/json"}
r = requests.get("http://localhost:8080/StudentService/rest/insert/get1", data=title, headers=headers)

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