Difference between these python code samples?

Question

I'm a python beginner and I'm trying to figure out the following below two python code samples. Both code looks same but printing a different result. The main function of the code is divisor summation.

CODE 1:

def divisor_sum(n):
 no_div = 0
 tot = int(n / 2) + 1
 for i in range(1,tot):
 if n % i == 0:
 no_div += 1
 print no_div

CODE 2:

def divisor2(m):
 max_div = int(m / 2) + 1
 val = 0
 for x in range(1, max_div):
 if m % x == 0:
 val += x
 print val

when calling the function?

divisor_sum(6)
divisor2(6)

Code ouput:

3
6

How it is producing two different results when both code samples are same?

Answer 1

Not exactly the same code:

CODE 1:

no_div += 1

CODE 2:

val += x

Answer 2

The first variant increments by 1 when a divisor is encountered:

no_div += 1

The second variant increments by the divisor:

val += x

This means that the first variant counts the number of divisors. The second variant sums the values of the divisors.

The divisors of 6 are 1, 2 and 3. So, there are a total of 3 divisors whose values sum to 6.

• Rishi Dua: This answer is a duplicate of the one given by @dreyescat
• PR_01: @David But for no of divisor for six is four and its printing 3. any idea ?
• David Heffernan: @Stux it doesn't include the number itself when counting divisors. That's the / 2.
• David Heffernan: I'm glad my explanations helped

Answer 3

Code in first function i.e divisor_sum() will be giving you the count of divisors of a number (then name of function is misleading). On the other hand code in the second function i.e divisor2() will give you sum of all the divisors of a number.

both function has different code :

divisor_sum() has : "no_div += 1 " that means increment no_div by 1 divisor2() has :"val += x" which means increment the value of val by x i.e if x=2 then val will become val+2.