Start HTTP/HTTPS server, python -m SimpleHTTPServer

Question

I am trying to start HTTPS server on my localhost, but getting below error. I have opened cmd as an administrator.

C:\Windows\system32>python -m SimpleHTTPServer
Traceback (most recent call last):
 File "C:\Python27\lib\runpy.py", line 162, in _run_module_as_main
 "__main__", fname, loader, pkg_name)
 File "C:\Python27\lib\runpy.py", line 72, in _run_code
 exec code in run_globals
 File "C:\Python27\lib\SimpleHTTPServer.py", line 224, in <module>
 test()
 File "C:\Python27\lib\SimpleHTTPServer.py", line 220, in test
 BaseHTTPServer.test(HandlerClass, ServerClass)
 File "C:\Python27\lib\BaseHTTPServer.py", line 595, in test
 httpd = ServerClass(server_address, HandlerClass)
 File "C:\Python27\lib\SocketServer.py", line 419, in __init__
 self.server_bind()
 File "C:\Python27\lib\BaseHTTPServer.py", line 108, in server_bind
 SocketServer.TCPServer.server_bind(self)
 File "C:\Python27\lib\SocketServer.py", line 430, in server_bind
 self.socket.bind(self.server_address)
 File "C:\Python27\lib\socket.py", line 224, in meth
 return getattr(self._sock,name)(*args)
socket.error: [Errno 10013] An attempt was made to access a socket in a way forb
idden by its access permissions

• Veedrac: Have you looked this up? There are a lot of results on the Google. I'm not going to close as duplicate because I don't know enough to make the judgement, but I'd expect you to at least point out how they don't apply when asking the question.
• garg10may: Yes saw answers which discuss trying telnet, i get below error, C:\Windows\system32>telnet 127.0.0.1 80 'telnet' is not recognized as an internal or external command, operable program or batch file. Also changed from normal to admin account still same erorr, simultaneously reading over if something works.

Answer 1

Your windows firewall may block python from listening. Additionaly, try adding a different port number higher than 1024 to the command line and see if it helps.

• falsetru: If unspecified, SimpleHTTPServer uses port 8000.
• garg10may: Ok it started on port 2000, but how can I ensure if some process in running on 8000 and how do I stop that, does running on different port matters.
• garg10may: @ApriOri is shows systemprocess with PID 4, firewall is definitely not blocking, since when I started on port 2000 it poped up and I allowed it.

Answer 2

I was not able to start since some service is already running on 8000, I was able to successfully start the service on another port 2000

C:\>python -m SimpleHTTPServer 2000
Serving HTTP on 0.0.0.0 port 2000 ..

One can get the PID/status for port 8000 by netstat -ano

C:\>netstat -ano
Active Connections
 Proto Local Address Foreign Address State PID
 TCP 0.0.0.0:912 0.0.0.0:0 LISTENING 2544
 TCP 0.0.0.0:8000 0.0.0.0:0 LISTENING 4
 TCP 0.0.0.0:19781 0.0.0.0:0 LISTENING 3100

shows PID 4 which is a system process.