Hi I want to create a JSON array.
I have tried using:
JSONArray jArray = new JSONArray();
while(itr.hasNext()){
int objId = itr.next();
jArray.put(objId, odao.getObjectName(objId));
}
results = jArray.toString();
Note: odao.getObjectName(objId) retrieves a name based on the "object Id" which is called objId.
However I get a very funny looking array like
[null,null,null,"SomeValue",null,null,null,null,null,null,null,null,null,null,null,null,null,null,null,"AnotherValue",null,null,null,null,null,null,null,null,null,null,"SomethingElse","AnotherOne","LastOne"]
With only "LastOne" being displayed when I retrieve it using jQuery.
The Array SHould look like
{["3":"SomeValue"],["40":"AnotherValue"],["23":"SomethingElse"],["9":"AnotherOne"],["1":"LastOne"]}
The numbers aren't showing up at all for some reason in the array that I am getting.
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You have a JSON Object of JSON arrays?Buhake Sindi– Buhake Sindi2010年03月30日 09:41:25 +00:00Commented Mar 30, 2010 at 9:41
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1Whatever you get, it shouldn't look like that. Arrays are [foo,bar,baz] while objects are { "foo": "value", "bar": "value", "baz": "value" }. You seem to have your {} and [] confused.Quentin– Quentin2010年03月30日 09:41:42 +00:00Commented Mar 30, 2010 at 9:41
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1Thanks everyone, I got something from each answer. In the end I realised my question wasn't expressed exactly as it should have been, but your answers solved my problem.Ankur– Ankur2010年03月30日 13:32:02 +00:00Commented Mar 30, 2010 at 13:32
3 Answers 3
For your quick Solution:
JSONArray jArray = new JSONArray();
while (itr.hasNext()) {
JSONObject json = new JSONObject();
int objId = itr.next();
json.put(Integer.toString(objId), odao.getObjectName(objId));
jArray.put(json);
}
results = jArray.toString();
Based on T. J. Crowder's response, my solution does this:
[{"3":"SomeValue"},
{"40":"AnotherValue"},
{"23":"SomethingElse"},
{"9":"AnotherOne"},
{"1":"LastOne"}
]
Refer to Jim Blackler's comment of what you're doing wrong.
Comments
The clue is in the documentation for JSONArray for method put(int index, String value)
If the index is greater than the length of the JSONArray, then null elements will be added as necessary to pad it out.
2 Comments
objId, but that's easy enough.What you've quoted for your "The object should look like" is invalid JSON. It's an object (delimited by { and }) but then it has values within it that don't have any keys. See json.org for the syntax of JSON.
If you want this:
{"3":"SomeValue",
"40":"AnotherValue",
"23":"SomethingElse",
"9":"AnotherOne",
"1":"LastOne"
}
...use JSONObject instead, and turn your objIds into keys when putting the entries in, e.g.:
JSONObject obj = new JSONObject();
while(itr.hasNext()){
int objId = itr.next();
obj.put(String.valueOf(objId), odao.getObjectName(objId));
}
results = obj.toString();
If you want this:
[{"3":"SomeValue"},
{"40":"AnotherValue"},
{"23":"SomethingElse"},
{"9":"AnotherOne"},
{"1":"LastOne"}
]
...see The Elite Gentleman's answer (that's a JSONArray of JSONObjects).