Django Intro Tutorial - Invoke Python Shell

Question

I am new to django and am starting to go through the documenation and the poll tutorial. Install etc has been no problem and I have gotten as far as creating and activating the simple model however I am now trying to invoke the Python shell using

python manage.py shell

but I keep getting the below error each time.

C:\Users\Owner\Desktop\Programming\Djang\mysite>python manage.py shell
Traceback (most recent call last):
 File "manage.py", line 10, in <module>
 execute_from_command_line(sys.argv)
 File "C:\python27\lib\site-packages\django\core\management\__init__.py", line
399, in execute_from_command_line
 utility.execute()
 File "C:\python27\lib\site-packages\django\core\management\__init__.py", line
392, in execute
 self.fetch_command(subcommand).run_from_argv(self.argv)
 File "C:\python27\lib\site-packages\django\core\management\base.py", line 242,
 in run_from_argv
 self.execute(*args, **options.__dict__)
 File "C:\python27\lib\site-packages\django\core\management\base.py", line 285,
 in execute
 output = self.handle(*args, **options)
 File "C:\python27\lib\site-packages\django\core\management\base.py", line 415,
 in handle
 return self.handle_noargs(**options)
 File "C:\python27\lib\site-packages\django\core\management\commands\shell.py",
 line 81, in handle_noargs
 self.run_shell(shell=interface)
 File "C:\python27\lib\site-packages\django\core\management\commands\shell.py",
 line 61, in run_shell
 return getattr(self, shell)()
 File "C:\python27\lib\site-packages\django\core\management\commands\shell.py",
 line 44, in ipython
 ip()
 File "C:\python27\lib\site-packages\django\core\management\commands\shell.py",
 line 37, in _ipython
 from IPython import start_ipython
 File "C:\python27\lib\site-packages\IPython\__init__.py", line 43, in <module>
 from .config.loader import Config
 File "C:\python27\lib\site-packages\IPython\config\__init__.py", line 16, in <
module>
 from .application import *
 File "C:\python27\lib\site-packages\IPython\config\application.py", line 29, i
n <module>
 from IPython.external.decorator import decorator
 File "C:\python27\lib\site-packages\IPython\external\decorator\__init__.py", l
ine 4, in <module>
 from ._decorator import *
 File "C:\python27\lib\site-packages\IPython\external\decorator\_decorator.py",
 line 165
 print('Error in generated code:', file=sys.stderr)
 ^
SyntaxError: invalid syntax

Thanks in advance for any help on this as although I have some experience in Python I'm finding it very hard to follow the Traceback above.

• SingleNegationElimination: It looks like you have python3 code in your python2 library. you cannot do that. Where did you get that IPython install?

Answer 1

You are using a Python 3 library (and not backward compatible) with the Python 2.7 version. You need either to reinstall ipython for Python 2 (in C:\python27) or upgrade to Python 3 (and install ipython in C:\python3)

Django is officially compatible with Python 3 since the 1.6 version.

• user3675339: That worked for me thank you very much. From my perspective is there anything in the Traceback above that would have made it obvious that there was an issue with compatibility (so I can know for again)?
• Maxime Lorant: @user3675339 The hint there was the fact there is C:\python27 in your path and the error occurred on the print line, because it became a function in Python 3: docs.python.org/3.0/whatsnew/3.0.html#print-is-a-function Don't forget to accept the answer if it helps you :) meta.stackexchange.com/questions/5234/…