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I'm trying to run a python script from another script using the following method:

from subprocess import call
call(['python script.py'])

but I'm getting the following error:

OSError: [Errno 2] No such file or directory

The files are both in the same directory. Help please.

asked Apr 19, 2014 at 18:00
1
  • Have you considered to put the code inside script.py inside functions and use import script; value = script.some_function(a, b) instead of running it as a subprocess? Commented Apr 19, 2014 at 23:30

2 Answers 2

1

Specify python and script.py as separated items:

call(['python', 'script.py'])
answered Apr 19, 2014 at 18:01
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1

If the parent script is run from a different directory then you need a way to find where the script is stored:

#!/usr/bin/env python
import os
import sys
from subprocess import check_call
script_dir = os.path.dirname(sys.argv[0])
check_call([sys.executable or 'python', os.path.join(script_dir, 'script.py')])

See also How to properly determine current script directory in Python?

answered Apr 19, 2014 at 23:43

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