Run Python module with absolute path

Question

For this file layout:

devel/
 pkg/
 __init__.py
 moduleA.py
 moduleB.py
 test/
 __init__.py
 test_A.py
 test_B.py

If I am in the directory which contains the pkg (devel), I can run:

python -m pkg.test.test_A

But what if I want to run the same but with absobule path? I tried:

python -m /Users/me/docs/devel/pkg.test.test_A

Assuming I don't want to do the following and change the directory in my bash script:

cd /Users/me/docs/devel/
python -m pkg.test.test_A

Is there any direct way from python command?

Answer 1

Add /Users/me/docs/devel to your module search path:

PYTHONPATH=/Users/me/docs/devel python -m pkg.test.test_A

• Diolor: So that's the only way? Because you know, you can run any sole file with the absolute path python /path/to/file/file.py. Thanks
• chepner: Either way should work, although note that you can't mix file paths and dotted module names; you would need python /Users/me/docs/devel/pkg/test/testA.py.
• Diolor: Yes I tried that unsuccessfully on my first attempt. I have relative imports (from .. import) inside the testA so I can only run it as a module. Pythonpath should be fine. Thank you