response with [object object] in JSON

Question

When i execute my page with JSON always have this response: [object object]. i have read in other post is a problem with not exist field, but this error appear too comment

$.each(result, function(i, row) { 
 console.log(JSON.stringify(row)); 
 $('#data-list').append('<li><a href="" data-id="' + row.id+ '"><h3>' + row.nombre + '</h3><p>' + row.denominacion + '</p></a></li>');
});

My javascript is:

$(document).on('pageinit', '#home', function(){ 
 var stuff = {
 id:null,
 nombre:null,
 precio:null,
 denominacion:null
 };
 var jsonString = JSON.stringify(stuff);
 $.ajax({
 url: "http://www.domain.com/ws.php?TIPO=OK" ,
 crossDomain: true,
 type:"GET",
 contentType: "application/json; charset=utf-8",
 dataType: "jsonp",
 async: true,
 data: jsonString,
 success: function (result) {
 alert(result);
 $.each(result, function(i, row) {
 console.log(JSON.stringify(row));
 $('#data-list').append('<li><a href="" data-id="' + row.id+ '"><h3>' + row.nombre + '</h3><p>' + row.denominacion + '</p></a></li>');
 });
 $('#data-list').listview('refresh');
 },
 error: function(xhr, status, error){
 console.log(status + '; ' + error+ ';');},
 jsonpCallback:function(response) {
 console.log('callback success'+response);
 }
 }); 
 });

In webserver is very simple only do a select and encapsule in JSON , i try with Content-type: application/javascript" and "Content-type: application/json" but same result,this is web service code

<?php
 include($DIRCONF . 'conf/VARIABLES.ini.php'); //incluimos configuración
 include($DIRCONF . 'JSON.php'); $tipo=$_GET['TIPO']; $json = new Services_JSON;
$conexion = mysql_connect(SERVIDOR_MYSQL, USUARIO_MYSQL, PASSWORD_MYSQL); mysql_select_db(BASE_DATOS, $conexion);
$que = "SELECT * FROM `DATOS`";
$res = mysql_query($que, $conexion) or die(mysql_error());
while ($row = mysql_fetch_assoc($res)) {
 $data[] = $row; } //Cerramos la conexion a la base de datos mysql_close($conexion);
//header("Content-type: application/javascript"); header("Content-type: application/json"); echo json_encode($data) ; ?>

Answer 1

[object object] is what JavaScript gives you when you attempt to use an object as if it were a string. It is possible that your code is fine, but console.log('callback success'+response); is never going to log useful information. This might work:

console.log('callback success: ' + JSON.stringify(response));

• alou: console.dir might also be an option
• Roberto: which this log show "callback success:undefined" page.html.html (línea 44) (Line of log) parsererror; Error: undefined was not called;[object Object], what mean this, men arrive function callback not defined values??? page.html (línea 41) (This line is where is function error)

Answer 2

I can find solution problem was Webservice, If you use jsonp: 'jsoncallback' need in WS return $_GET['jsoncallback'] how JSON object, if not put it, don't find any object and do error.

For example:

echo $_GET['jsoncallback'] . '(' . json_encode($records) . ');';