Converting Array of Objects into Array of Arrays

Question

There is a condition where i need to convert Array of objects into Array of Arrays.

Example :-

arrayTest = arrayTest[10 objects inside this array]

single object has multiple properties which I add dynamically so I don't know the property name.

Now I want to convert this Array of objects into Array of Arrays.

P.S. If I know the property name of object then I am able to convert it. But i want to do dynamically.

Example (If I know the property name(firstName and lastName are property name))

var outputData = [];
for(var i = 0; i < inputData.length; i++) {
 var input = inputData[i];
 outputData.push([input.firstName, input.lastName]);
}

Answer 1

Converts Array of objects into Array of Arrays:

var outputData = inputData.map( Object.values );

• FreeSoftwareServers: Only thing, I had to collect keys from obj and then added using unshift to insert into first position! Otherwise, perfect oneliner!

Answer 2

Try this:

var output = input.map(function(obj) {
 return Object.keys(obj).sort().map(function(key) { 
 return obj[key];
 });
});

• KiddoDeveloper: Thank you Sabof. I got it what i wanted. Actually I am working on a jQuery Datatable so for your help i get the data. Now i need Property name for Datatable columns heading. Can you tell me how i can get single object's property name??
• sabof: @user3292436 Just use this bit: Object.keys(obj).sort()
• KiddoDeveloper: hi Sabof. I solved my problem but i couldn't understand the logic behind of MAP method. I have searched on google and found some answer (Its return an array and etc.) but couldn't understand. Can you please explain??
• sabof: @Mohit map creates a new array, where each item is the result of function applied to an item in the original array
• Alexis.Rolland: Hi @sabof, is the sort important here? Can I skip it if I don't want to alter the order of my values?

Answer 3

Use the for-in loop

var outputData = [];
for (var i in singleObject) {
 // i is the property name
 outputData.push(singleObject[i]);
}