How to get multiple parameters with same name from a URL in JavaScript

Question

A question asked without possibly an end is how do I get variable from a URL. In all my searching I have found several very good ways to get A=aValue from the url.

But my question is I need

?Company=FLHS&Device=Crosstown_PCC_01&A=aValue&A=secondAValue

I need an array of the two A's in the url and I need to know that aValue was the first one and secondAValue was the second

I have jquery Mobile.

Update

So this is what I have now

var urlParamDevice = getURLParameter('DeviceID');
function getURLParameter(name) {
 return decodeURI(
 (RegExp(name + '=' + '(.+?)(&|$)').exec(location.search) || [, null])[1]
 );

The getURLParameter(name) needs to be a little more robust.

Update 2, 2014年03月07日 Here is what I came up with from the suggested answer

function getQueryParams(name) {
 qs = location.search;
 var params = [];
 var tokens;
 var re = /[?&]?([^=]+)=([^&]*)/g;
 while (tokens = re.exec(qs))
 { 
 if (decodeURIComponent(tokens[1]) == name)
 params.push(decodeURIComponent(tokens[2]));
 }
 return params;
}

• Rainbolt: There are examples of passing arrays (or any other object) as a parameter here: api.jquery.com/jQuery.param
• Brian Hanf: Thanks, trying to get an array from the URL not pass one.

Answer 1

function getparamNameMultiValues(paramName){
	 var sURL = window.document.URL.toString();
	 var value =[];
	 if (sURL.indexOf("?") > 0){
	 var arrParams = sURL.split("?");
	 var arrURLParams = arrParams[1].split("&");
	 for (var i = 0; i<arrURLParams.length; i++){
	 var sParam = arrURLParams[i].split("=");
	 console.log(sParam);
	 if(sParam){
		 if(sParam[0] == paramName){
		 	if(sParam.length>0){
		 		value.push(sParam[1].trim());
		 	}
		 }
	 }
	 }
	 }
	 return value.toString();
	}

• Nuageux: Welcome to SO, posting a code as an answer might not be very useful without explanation. Could you edit your answer to had some explanation? You might be interested to read how to write a good answer

Answer 2

That would be by doing as: https://stackoverflow.com/a/1099670/1020854 - But with a little modification

function getQueryParams(qs) {
 qs = qs.split("+").join(" ");
 var params = [], tokens,
 re = /[?&]?([^=]+)=([^&]*)/g;
 while (tokens = re.exec(qs)) {
 params.push({k:decodeURIComponent(tokens[1]),v:decodeURIComponent(tokens[2])});
 }
 return params;
}
var obj = 
 getQueryParams("?Company=FLHS&Device=Crosstown_PCC_01&A=aValue&A=secondAValue")
obj[0] is {k: "Company", v: "FLHS"}
obj[1] is {k: "Device", v: "Crosstown_PCC_01"}
obj[2] is {k: "A", v: "aValue"}
obj[3] is {k: "A", v: "secondAValue"}

• Brian Hanf: Close. I think I can make it work. I only want the "A"
• fiinix: I was not entierly sure what data you where after, but this does indeed extract all the "A"'s
• fiinix: And she only wants the D, heh jokes aside :P

Answer 3

Sometimes this will work:

A[]=aValue&A[]=secondAValue

Otherwise you can do this:

A_1=aValue&A_2secondAValue

You can split on the the underscore or use mostly any character of your choice to differentiate values of querystring "A"

• Brian Hanf: I understand, but that is not how the information is coming. I have to consume, not create. It's possible that we have 20 or 30 A's
• Jay: If you have the whole querystring, I suppose you could split on '&' and then on '=' and build a multimap/hashmap or list of arrays based on the keyname