Converting to For loop javascript

Question

I have the following js code:

 function splitter(somestr){
 "use strict";
 var bb0 = somestr.split(":");
 return bb0;
}
 var plist = [t_str, f_str, c_str, d_str, e_srt, o_str, k_str];
 var aa0 = splitter(plist[0]);
 var aa1 = splitter(plist[1]);
 var aa2 = splitter(plist[2]);
 var aa3 = splitter(plist[3]);
 var aa4 = splitter(plist[4]);
 var aa5 = splitter(plist[5]);
 var aa6 = splitter(plist[6]);

I wanted to convert this into a for loop:

 for (var k = 0; k < plist.length; k++) {
 var a = plist[k];
 var aa[k] = splitter(a);
 return aa[k];}

What am i doing wrong, am I calling the splitter function within the loop incorrectly?

• Sterling Archer: Without knowing what is inside the array, the expected output vs what you get, we can't answer this.
• tewathia: aa[0] is not the same as aa0
• Felix Kling: You are calling the function correctly, but you cannot have a variables declaration like var aa[k]. Instead of having variables with numeric indexes, use an array instead. So, before the loop: var aa = []; and in the loop aa[k] = ...;.
• user3213563: each element n the array plist is in the form 8:20 i.e. a time. The splitter function splits the desired element in p-list into a 2-wide array.

Answer 1

I'm guessing you want to store the values in aa, meaning you need to move it up in scope:

var aa = [];
for (var k = 0; k < plist.length; k++) {
 var a = plist[k];
 aa[k] = splitter(a);
}
// Do something with aa

Answer 2

I am assuming you want to perform the splitter operation on each element of the plist array and store the results somewhere. Try:

var aa = plist.map(function(element){return splitter(element);})

Answer 3

Following doesn't make sense

function splitter(somestr){
 **"use strict"; // This is not making sense**
 var bb0 = somestr.split(":");
 return bb0;

}

and also in the following a must be the an array to whom you are going to assigning values.

for (var k = 0; k < plist.length; k++) {
 var a = plist[k];
 var aa[k] = splitter(a);
 return aa[k];}

• Sterling Archer: Are you saying strict mode is not a good idea or do you not know what strict mode is?
• Teemu: @user2951753 What??? Please read about Strict mode. Also why in world a should be an array? a is passed to splitter(), and treated as a string there...
• user3213563: I've commented strict mode out.