Replace Multiple String at Once With Regex in Javascript

Question

I tried this : Replace multiple strings at once And this : javascript replace globally with array how ever they are not working.

Can I do similar to this (its PHP):

$a = array('a','o','e');
$b = array('1','2','3');
str_replace($a,$b,'stackoverflow');

This result will be :

st1ck2v3rfl2w

I want to use regex at the same time. How can I do that ? Thank you.

• Naresh Kumar: **You can find a replace a string using delimiters ** click here
• Stephen M. Harris: Does this answer your question? Replace multiple strings at once

Answer 1

var str = "I have a cat, a dog, and a goat.";
var mapObj = {
 cat:"dog",
 dog:"goat",
 goat:"cat"
};
str = str.replace(/cat|dog|goat/gi, function(matched){
 return mapObj[matched];
});

Check fiddle

Answer 2

One possible solution:

var a = ['a','o','e'],
 b = ['1','2','3'];
'stackoverflow'.replace(new RegExp(a.join('|'), 'g'), function(c) {
 return b[a.indexOf(c)];
});

As per the comment from @Stephen M. Harris, here is another more fool-proof solution:

'stackoverflow'.replace(new RegExp(a.map(function(x) {
 return x.replace(/[-\/\\^$*+?.()|[\]{}]/g, '\\$&');
}).join('|'), 'g'), function(c) {
 return b[a.indexOf(c)];
});

N.B.: Check the browser compatibility for indexOf method and use polyfill if required.

• Stephen M. Harris: This can break if the find strings contain any special regex chars. Here's an improved version (and also cross-browser w/o polyfills) stackoverflow.com/a/37949642/445295
• VisioN: @StephenM.Harris I have added another variant, that will take care of the edge cases with special regex characters.

Answer 3

You can use delimiters and replace a part of the string

var obj = {
 'firstname': 'John',
 'lastname': 'Doe'
}
var text = "My firstname is {firstname} and my lastname is {lastname}"
console.log(mutliStringReplace(obj,text))
function mutliStringReplace(object, string) {
 var val = string
 var entries = Object.entries(object);
 entries.filter((para)=> {
 var find = '{' + para[0] + '}'
 var regExp = new RegExp(find,'g')
 val = val.replace(regExp, para[1])
 })
 return val;
}