Javascript function stringing

Question

Could anyone explain to me why the third alert function is simply not called?, and a possible reading resource in relation to the error.

<script type="text/javascript">
$( document ).ready(function() {
 myFunction();
});
function myFunction()
{
 alert("First Function");
 mySecondFunction(function () {
 alert("Third Function");
 });
}
function mySecondFunction()
{
 alert("Second Function");
}

• Santosh Joshi: because you are not passing parameter to mySecondFunction
• DontVoteMeDown: @SantoshJoshi he's passing a parameter, a function. He's just not executing it.
• A. Wolff: FYI $( document ).ready(function() { myFunction(); }); in your case could be wrote $(myFunction)
• Santosh Joshi: @DontVoteMeDown, my bad, i mean to say he has not declared function to take any paramaters,

Answer 1

Because you're doing nothing with that function in the parameter. You can do this:

function mySecondFunction(func)
{
 alert("Second Function");
 func();
}

Answer 2

You are passing anonymous function function () { alert("Third Function"); } as a parameter to mySecondFunction(), but you're not calling this anonymous function anywhere inside mySecondFunction().

This would work:

function mySecondFunction(callback)
{
 alert("Second Function");
 callback();
}

• garyamorris: Thanks for the help, you were spot on.