syntax error on `If` line

Question

My code:

#!/usr/bin/env python
def Runaaall(aaa):
 Objects9(1.0, 2.0)
def Objects9(aaa1, aaa2):
 If aaa2 != 0: print aaa1 / aaa2

The error I receive:

$ python test2.py 
 File "test2.py", line 7
 If aaa2 != 0: print aaa1 / aaa2
 ^
SyntaxError: invalid syntax

I'm at a loss to why this error is happening.

• S.Lott: What python tutorial are you using to learn the language?
• SilentGhost: @S.Lott: :) I guess he hasn't followed your advice here stackoverflow.com/questions/1573548/…
• S.Lott: @SilentGhost: Good point. I rarely check to see who asks the question. This appears to be two questions with the same bad behavior: type random stuff and hope it works.
• smci: The 'if' keyword must be lowercase. But this is a good catch that the syntax error highlighting caret points to 'aaa2' not the capital 'If', even in Python 3.12

Answer 1

if must be written in lower case.

Furthermore,

• Write function names in lower case (see PEP 8, the Python style guide).
• Write the body of an if-clause on a separate line.
• Though in this case you'll probably not run into trouble, be careful with comparing floats for equality.

• Since you've just started learning Python, you may want to get acquainted with writing parentheses around the arguments to print, since from Python 3 onwards, print is a function, not a keyword.
  To enforce this syntax in Python 2.6, you can put this at the top of your file:

  from __future__ import print_function
  

  Demonstration:

  >>> print 'test'
  test
  >>> from __future__ import print_function
  >>> print 'test'
   File "<stdin>", line 1
   print 'test'
   ^
  SyntaxError: invalid syntax
  >>> print('test')
  test
  

  For more on __future__ imports, see the documentation.

• Bartosz Radaczyński: the last point can be achieved by using from future import print_function on python 2.6
• Stephan202: Good point, Bartosz. I updated the answer with some more information.

Answer 2

It's the capital 'I' on "If". Change it to "if" and it will work.

Answer 3

How about

def Objects9(aaa1, aaa2):
 if aaa2 != 0: print aaa1 / aaa2

Python keywords are case sensitive, so you must write 'if' instead of 'If', 'for' instead of 'fOR', et cetera.